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3 years ago

The potential energy of a 25 kg bicycle resting at the top of a 3 m high hill is _______ J

Physics

2 answers:

HACTEHA [7]3 years ago

7 0

Hello!

The potential energy of a 25 kg bicycle resting at the top of a 3 m high hill is _______ J

If: 1 Joule = 1 kg.m²/s²

We have the following data:

GPE (Gravitational Potential Energy) = ? (in J)

m (mass) = 25 kg

g (gravity) ≈ 9.81 m/s²

h (height) = 3 m

We apply the data to the formula of the gravitational potential energy, we have:

$GPE = m*g*h$

$GPE = 25\:kg*9.81\:\dfrac{m}{s^2} *3m$

$GPE = 735.75\:kg*\dfrac{m^2}{s^2}$

$\boxed{\boxed{GPE = 735.75\:J}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

735.75 J

________________________

$\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

frozen [14]3 years ago

5 0

The potential energy:
E p = m · g · h
m = 25 kg, g = 9.81 m/s², h = 3 m
E p = 25 kg · 9.81 m/s² · 3 m = 735.75 J

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3 years ago

Given a 10-V power supply, would a 20-ohm resistor and a 5-ohm resistor need to be arranged in parallel or in series to generate

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Answer:

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Explanation:

We are given 10 voltage power source and we have two Resistors with resistance of 20 ohm and 5ohm.

We need to find the orientation in which these two resistors would be arranged so that the circuit could get a current of 2.5Ampere.

Using ohm's law we have

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Now the orientation of the resistors are in parallel so the current will be divided.

we know that the current will divide in opposite manner the arm which provides more resistance less current will flow from there and vice versa.

We know that the voltage in parallel remains same

In 20 ohm resistance

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and i1+i2 = 0.5+2= 2.5A which means our calculation is correct.

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A ball is bouncing to a height that is 1/3 of the previous height after every bounce. What kind of sequence is this? How could y

tamaranim1 [39]

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