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Varvara68 [4.7K]
3 years ago
5

Help in physics please. Need asap :(((​

Physics
1 answer:
uranmaximum [27]3 years ago
6 0

Answer:

which class you are studying hear the everything is based on the tangent line I didn't even handle this I am sorry

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If an ice skater with a mass of 50 kg was accelerating at 10 m/s and is on her way to hit a
IrinaK [193]

500N

Explanation:

Given parameters:

Mass of skater = 50kg

Acceleration = 10m/s

Unknown:

Force  = ?

Solution;

Force is a push or pull on a body. it is given as the product of mass and acceleration:

               Force = mass x acceleration

    Input the parameters:

                  Force = 50 x 10 = 500N

She hits the wall with a force of 500N

Learn more:

Force brainly.com/question/3820012

#learnwithBrainly

5 0
3 years ago
TP-4 When are lights required to be installed on a trailer?
kari74 [83]

Answer:

Light are required on every trailer

Explanation:

6 0
4 years ago
A cannon shoots a cannon ball. The momentum of the cannon as compared to the cannon ball is:
Alika [10]
B. I hope this helped!
6 0
3 years ago
Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has an initial momentum magnitude of 600 kg-m/s. What is it
kati45 [8]

Answer:

Initial speed of the spaceship 1, v = 2 m/s

Explanation:

Given that :

Mass of spaceship 1 and 2 that have equal mass are 300 kg

Initial momentum of the spaceship 1 is 600 kg-m/s

To find :

We need to find the initial momentum of spaceship 1.

Solve :

The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :

p=mv

v=\dfrac{p}{m}

v=\dfrac{600\ kg-m/s}{300\ kg}

v = 2 m/s

Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.

6 0
3 years ago
. A light bulb glows because of it’s resistance, and the brightness of the bulbincreases with the electrical power delivered to
sesenic [268]

Complete Question

The complete question is shown in the first uploaded image

Answer:

a

When the both bulb are in the circuit  bulb B glows equally brighter to bulb A

This because the power delivered to the both bulb are equal

b

The bulb A on the right will glow brighter than the bulb A on the left due to the fact that the power supplied to bulb A on the right is higher than that gotten by bulb A on the left.

Explanation:

From the question we are been told that the two bulbs are identical

So their resistance denoted by R is the same

Considering the left circuit  where the two bulbs are connected in series which mean that the same current is passing through them

               R_A  =R_B =R

                i_A = i_B  =i

               R_{eq} = R_1 +R_2 = 2R

                       i = \frac{V}{2R}  

The power that is been deposited on the circuit is evaluated as

                   P_A = i^2R

                   P_A = \frac{V^2}{4R}

                  P_B = i^2R

                   P_B = \frac{V^2}{4R}

For the fact that the power deposited on the bulbs are the same they will glow equally

When B is now removed and only A is left

                R_{eq} = R_A = R

                   i = \frac{V}{R}

                   P'_A = i^2R

                    P'_A = \frac{V^2}{R}

For the fact that its only bulb A that is on that right circuit the power delivered  to it would be greater compared to the left circuit bulb A

7 0
3 years ago
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