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2 years ago

What is the Lewis structure for Iodide?

Chemistry

1 answer:

jasenka [17]2 years ago

5 0

Answer:

In the Lewis structure for IF5 you'll need to put a total of 12 valence electrons on the Iodine atom in order to draw the Lewis structure. Remember that Iodine (I) can hold more than eight valence electrons. For the IF5 Lewis structure, calculate the total number of valence electrons for the IF5 molecule

Explanation:

<em> I be knowing hope this helps</em>

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Calculate the amount of heat energy, in kJ, needed to increase the temperature of 200g of water by 300 C.

shtirl [24]

Answer:

Q = 246 kJ

Explanation:

It is given that,

Mass of water, m = 200 g

Let initial temperature, $T_i=5^{\circ}$

Final temperature of water, $T_f=300^{\circ} C$

We know that the specific heat capacity of water, $c=4.18\ J/g-^{\circ} C$

So, the heat energy needed to raise the temperature is given by :

$Q=mc\Delta T\\\\Q=200\times 4.18\times (300-5)\\\\Q=246620\ J$

Q = 246 kJ

So, the heat energy of 246 kJ is needed.

8 0

3 years ago

The definition of canon

Aloiza [94]

a general law, rule, principle, or criterion by which something is judged

a collection or list of sacred books accepted as genuine

3 0

3 years ago

Read 2 more answers

The rate of disappearance of HBr in the gas phase reaction 2HBr(

Iteru [2.4K]

The correct answer would be 0.1505 M/s. Given the rate of disapperance of HBr, we can easily calculate the rate of apearance of the products by looking at the coefficients of the substances in the reaction. In this case, for every two moles of HBr, 1 mole of Br2 is being produced so the reaction rate would be:

- 1/2 (r(HBr)) = rBr2
- 1/2 (-0.301) = rBr2
Rate of appearance of Br2 = 0.1505 M/s

3 0

2 years ago

Help please I really need it. :(

stich3 [128]

Answer:

the second answer

Explanation:

7 0

2 years ago

The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at

seraphim [82]

Answer:

the solubility of CaCO3 is 0.015g/l 25 °C

is favored at equilibrium

Explanation:

The Ksp of calcium carbonate in water at 25 °C is 2.25 x 10-8. CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq) What is favored at equilibrium?

solubility is the property of a solute to dissolve in a solvent(liquid, gas ) to form a solution(soution can be saturated ,unsaturated, or supersaturated)

CaCO3(s) <----> Ca2+ (aq) + CO3 2- (aq)

in partial dissociation , we can say

2.25x 10^-8= $Ca^{2+} +CO^{2-}_{3} }$

let Ca^2+=CO3^-2=S

2.25x10^-8=S*S

S^2=2.25x10^-8

S=0.00015mol/L

Converting that to g/l

the relative molecular mass of CaCO3=100g/mol

0.00015*100g/mol

0.015g/l

the solubility of CaCO3 is 0.015g/l @room temperature

is favored at equilibrium

5 0

2 years ago