Answer:
my observation is that i cant figure it out because googl_e is not telling me
Explanation:
it just wont
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The number of grams of oxygen present in a sample of this compound that contains 40.00 grams of S = 29.9g of oxygen
<h3>Calculation of quantity of Oxygen</h3>
The compound contains the following:
sulphur = 57.20%
Oxygen= 100 - 57.20 = 42.80%
If 57.20% of the sample contains 40g of sulphur then 42.80% of the sample will contain X.
Make X the subject of formula,
X = 42.8 × 40/57.20
X= 1712/57.20
X= 29.9g of oxygen
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Answer:
12 moles of water (H₂O)
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
6CO₂ + 6H₂O —> C₆H₁₂O₆ + 6O₂
From the balanced equation above,
6 moles of H₂O reacted to produce 1 mole of C₆H₁₂O₆.
Finally, we shall determine the number of mole of H₂O required to produce 2 moles of C₆H₁₂O₆. This can be obtained as follow:
From the balanced equation above,
6 moles of H₂O reacted to produce 1 mole of C₆H₁₂O₆.
Therefore, Xmol of H₂O will react to produce 2 moles of C₆H₁₂O₆ i.e
Xmol of H₂O = 6 × 2
Xmol of H₂O = 12 moles.
Thus, 12 moles of water (H₂O) is needed to produce 2 moles of glucose (C₆H₁₂O₆).
Answer:
In styrene, there is a phenyl group which is electron-withdrawing. So the electronic density in the double bonds increases, hence easy to associate as monomers. While in methoxystyrene, there is a carbonyl group which is not electron deficient. so no easy association with monomers.
Explanation: