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lubasha [3.4K]
3 years ago
6

Please help! What happens when thrust stays the same and mass increases?

Physics
1 answer:
Igoryamba3 years ago
4 0

when force stays the same and the mass increases, the ACCELERATION DECREASES.

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What is the main aim of pokhara regional international airpot project​
rjkz [21]

Answer:

Explanation:

The main aim of pokhara regional international airpot project​ is to provide improved air transportation services to the people. It will also strengthen the country's civil aviation sector and contribute to economic and social development, as well as tourism.

hope this helps

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8 0
3 years ago
Read 2 more answers
Can anybody help me solve this problem? Thank you so much!
ser-zykov [4K]
Please ignore my comment -- mass is not needed, here is how to solve it. pls do the math

at bottom box has only kinetic energy
ke = (1/2)mv^2
v = initial velocity
moving up until rest work done = Fs
F = kinetic fiction force = uN = umg x cos(a)
s = distance travel = h/sin(a)
h = height at top
a = slope angle
u = kinetic fiction
work = Fs = umgh x cot(a)
ke = work (use all ke to do work)
(1/2)mv^2 = umgh x cot(a)
u = (1/2)v^2 x tan (a) / gh
4 0
3 years ago
A 5.00-g bullet is fired into a 900-g block of wood suspended as a ballistic pendulum. The combined mass swings up to a height o
Thepotemich [5.8K]

Answer:

The value is  KE_b =0.710 \ J

Explanation:

From the question we are told that

   The mass  of the bullet is m_b  = 5.00 \ g  = 0.005 \  kg

  The mass  of the wood is  m_w =  900 \  g  =  0.90\  kg

   The height attained by the combined mass is  h =  8.0 \ cm  =  0.08 \ m

Generally according to the law of energy conservation    

    KE _b  =  PE_c

Here KE_b is the kinetic energy of the bullet before collision.

and PE_c is the  potential  energy of the combined mass of bullet and wood at the height h which is mathematically represented as

      PE_m  =  [m_b  + m_w] *  g *  h

So

   KE_b =PE_c   = [0.005  + 0.90] * 9.8 *0.08

=> KE_b =0.710 \ J

3 0
3 years ago
Demarcus launches a small weight into the air. The weight takes 6.4 seconds to reach the ground again. At what time did the weig
Monica [59]
The answer is A.
During the process, the only force imposed on the small weight is gravity.
The time from launching to the highest is the same as the time from the highest to the ground. And the vertical velocity at 0 m/s is at the highest position.
5 0
3 years ago
The Milky Way has a diameter (proper length) of about 1.2×105 light-years. According to an astronaut, how many years would it ta
Dmitriy789 [7]

Answer:

t = 134834.31 years

Explanation:

First we find the speed of the ship:

v = 0.890 c

where,

v = speed of the ship = ?

c = speed of light = 3 x 10⁸ m/s

Therefore, using the values, we get:

v = (0.89)(3 x 10⁸ m/s)

v = 2.67 x 10⁸ m/s

Now, we find the distance in meters:

Distance = s = (1.2 x 10⁵ light years)(9.461 x 10¹⁵/1 light year)

s = 11.35 x 10²⁰ m

Now, for the time we use the following equation:

s = vt

t = s/v

t = (11.35 x 10²⁰ m)/(2.67 x 10⁸ m/s)

t = (4.25 x 10¹² s)(1 h/3600 s)(1 day/24 h)(1 year/365 days)

<u>t = 134834.31 years</u>

6 0
4 years ago
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