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Anna35 [415]
3 years ago
6

Can anybody help me solve this problem? Thank you so much!

Physics
1 answer:
ser-zykov [4K]3 years ago
4 0
Please ignore my comment -- mass is not needed, here is how to solve it. pls do the math

at bottom box has only kinetic energy
ke = (1/2)mv^2
v = initial velocity
moving up until rest work done = Fs
F = kinetic fiction force = uN = umg x cos(a)
s = distance travel = h/sin(a)
h = height at top
a = slope angle
u = kinetic fiction
work = Fs = umgh x cot(a)
ke = work (use all ke to do work)
(1/2)mv^2 = umgh x cot(a)
u = (1/2)v^2 x tan (a) / gh
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What is the change in momentum of a 50-kg rock that falls freely for 3 seconds?
Elan Coil [88]

Answer:

1470kgm/s

Explanation:

Given parameters:

Mass of the rock = 50kg

Time taken for the free fall  = 3s

Unknown:

Change in momentum = ?

Solution:

The change in momentum will be difference between the ending momentum and finishing momentum.

  Momentum is the product of mass and velocity

       Momentum  = mass x velocity

Initial momentum  = 0, the velocity is 0

Final momentum = mass x final velocity

      let us find the final velocity;

                V = U + gt

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity = 9.8m/s²

t is the time

                 V  = 0 + 9.8x3 = 29.4m/s

So;

 Change in momentum  = 50 x 29,4  = 1470kgm/s

6 0
3 years ago
What two factors are multiplied to determine wave speed
Rudiy27

you can determine it by the wavelenght and the period of the wave and the frequencey

7 0
3 years ago
What is 1.3 for PE=mgh and for KE=1(m)v^2 and E=PE+KE and V​
emmainna [20.7K]

Answer:

1.3 is equal to m times v to the second  times PK, meaning the answer to your question is 3.3 K

Explanation:

Have a gday!

8 0
3 years ago
Please help!! I'm stuck on this, could someone also explain if they can!! Will give brainiest if I can!!
Ann [662]
The answer is going to be c. hope that helped
8 0
3 years ago
A baboon pushes a 3.1 kg stone with 150 j of kinetic energy.<br> What is the stone’s speed?
azamat

The speed of the stone is 9.8 m/s

<u>Explanation:</u>

Given data,

Mass - 3 kg    K.E 150-J

We have to find the speed of the stone

We have the formula

K.E =1/2 m× v ²

Rewrite the equation as

v= √ 2×K.E/m

v= √2 ×150/ 3.1

v=9.83 m/s

The speed of the stone is 9.8 m/s

<u />

4 0
3 years ago
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