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Greeley [361]
2 years ago
9

Hey there!

Physics
2 answers:
eimsori [14]2 years ago
8 0

The time taken for the two balls to hit each other is 8 s.

The given parameters:

  • <em>Acceleration of the rocket, a = 2 m/s²</em>
  • <em>Length of the chamber, s = 4 m</em>
  • <em>Speed of the first ball, = V1 = 0.3 m/s</em>
  • <em>Speed of the second ball, V2 = 0.2 m/s</em>

The time taken for the two balls to hit each other is calculated by applying relative velocity formula as shown below;

(V_1 - (-V_2) )t = s\\\\(V_1 + V_2) t = s\\\\(0.3 + 0.2) t = 4\\\\0.5t = 4\\\\t = \frac{4}{0.5} \\\\t = 8 \ s

Thus, the time taken for the two balls to hit each other is 8 s.

Learn more about relative velocity here: brainly.com/question/17228388

blondinia [14]2 years ago
8 0

Answer:

S=ut+12at2

Where, u is the initial velocity

a is the acceleration and,

t is the time taken.

For the right ball, the equation can be written as:

S=(0.3)t+12(−2)t2

On the other hand, for the left ball, we get the equation as:

4−S=(0.2)t+12(2)t2

After substituting the value of S from one equation of the other, we can find the value of time, t, easily as:

t=8s

Explanation:

so sorry if this is wrong

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Two charges are located in the xx–yy plane. If q1=−4.10 nCq1=−4.10 nC and is located at (x=0.00 m,y=1.080 m)(x=0.00 m,y=1.080 m)
Gala2k [10]

Answer:

Explanation:

Due to first charge , electric field at origin will be oriented towards - ve of y axis.

magnitude

Ey = -8.99 x 10⁹ x 4.1 x 10⁻⁹ / 1.08² j

= - 31.6 j N/C

Due to second charge electric field at origin

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.2²+ .6²

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.8

= 18 N/C

It is making angle θ where

Tanθ = .6 / 1.2

= 26.55°

this field in vector form

= - 18 cos 26.55 i - 18 sin26.55 j

= - 16.10 i - 8.04 j

Total field

= - 16.10 i - 8.04 j + ( - 31.6 j )

= -16.1 i - 39.64 j .

Ex = - 16.1 i

Ey = - 39.64 j .

8 0
3 years ago
A hollow sphere of inner radius 8.82 cm and outer radius 9.91 cm floats half-submerged in a liquid of density 948.00 kg/m^3. (a)
kari74 [83]

Answer:

a) 0.568 kg

b) 474 kg/m³

Explanation:

Given:

Inner radius = 8.82 cm = 0.0882 m

Outer radius = 9.91 cm = 0.0991 m

Density of the liquid = 948.00 Kg/m³

a) The volume of the sphere = \frac{4\pi}{3}\times(0.0991^2-0.0882^2)

or

volume of sphere = 0.0012 m³

also, volume of half sphere = \frac{\textup{Total volume}}{\textup{2}}

or

volume of half sphere = \frac{\textup{0.0012}}{\textup{2}}

or

Volume of half sphere =0.0006 m³

Now, from the Archimedes principle

Mass of the sphere = Weight of the volume of object submerged

or

Mass of the sphere = 0.0006× 948.00 = 0.568 kg

b) Now, density =  \frac{\textup{Mass}}{\textup{Volume}}

or

Density = \frac{\textup{0.568}}{\textup{0.0012}}

or

Density = 474 kg/m³

8 0
2 years ago
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