Answer:

Explanation:
When two cars collide then the momentum of two cars will remains conserved
- Mass of two cars = 100 kg
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Speed of car B = - 10 m/s
-
After collision the speed of car B = +8 m/s
By momentum conservation equation


The net force on the larger mass in the horizontal direction (where we take the direction of F to be positive) is
F - T = 2Ma
where T is the magnitude of tension and a is the mass's acceleration.
The net force on the smaller mass in the vertical direction (upward is positive) is
T - Mg = Ma
If M = 1.0 kg and F = 60 N, then we end up with two equations with two unknowns,
60 N - T = (2.0 kg) a
T - (1.0 kg) (9.8 m/s²) = (1.0 kg) a
Eliminate a and solve for T :
(60 N - T) - 2 (T - (1.0 kg) (9.8 m/s²)) = (2.0 kg) a - 2 (1.0 kg) a
60 N - T - 2T + 19.6 N = (2.0 kg) a - (2.0 kg) a
40.4 N - 3T = 0
3T = 40.4 N
T = (40.4 N) / 3
T ≈ 13 N
Answer:
Transferring
Explanation:
It's just the transferring of heat
The formula for distance is speed times time.
So 3 times 6 would be 18 m/s
Answer:
the acceleration 
Explanation:
Given that:
the initial speed v₁ = 0 m/s i.e starting from rest ; since the car accelerates at a distance Δx = 6 miles in order to teach that final speed v₂ of 63.15 km/h.
So; the acceleration for the first 6 miles can be calculated by using the formula:
v₂² = v₁² + 2a (Δx)
Making acceleration a the subject of the formula in the above expression ; we have:
v₂² - v₁² = 2a (Δx)




Thus;
Assume the car moves in the +x direction;
the acceleration 