Question

Hey there!

Answer 1

The time taken for the two balls to hit each other is 8 s.

The given parameters:

• Acceleration of the rocket, a = 2 m/s²
• Length of the chamber, s = 4 m
• Speed of the first ball, = V1 = 0.3 m/s
• Speed of the second ball, V2 = 0.2 m/s

The time taken for the two balls to hit each other is calculated by applying relative velocity formula as shown below;

$(V_1 - (-V_2) )t = s\\\\(V_1 + V_2) t = s\\\\(0.3 + 0.2) t = 4\\\\0.5t = 4\\\\t = \frac{4}{0.5} \\\\t = 8 \ s$

Thus, the time taken for the two balls to hit each other is 8 s.

Learn more about relative velocity here: brainly.com/question/17228388

Answer 2

Answer:

S=ut+12at2

Where, u is the initial velocity

a is the acceleration and,

t is the time taken.

For the right ball, the equation can be written as:

S=(0.3)t+12(−2)t2

On the other hand, for the left ball, we get the equation as:

4−S=(0.2)t+12(2)t2

After substituting the value of S from one equation of the other, we can find the value of time, t, easily as:

t=8s

Explanation:

so sorry if this is wrong