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Greeley [361]
2 years ago
9

Hey there!

Physics
2 answers:
eimsori [14]2 years ago
8 0

The time taken for the two balls to hit each other is 8 s.

The given parameters:

  • <em>Acceleration of the rocket, a = 2 m/s²</em>
  • <em>Length of the chamber, s = 4 m</em>
  • <em>Speed of the first ball, = V1 = 0.3 m/s</em>
  • <em>Speed of the second ball, V2 = 0.2 m/s</em>

The time taken for the two balls to hit each other is calculated by applying relative velocity formula as shown below;

(V_1 - (-V_2) )t = s\\\\(V_1 + V_2) t = s\\\\(0.3 + 0.2) t = 4\\\\0.5t = 4\\\\t = \frac{4}{0.5} \\\\t = 8 \ s

Thus, the time taken for the two balls to hit each other is 8 s.

Learn more about relative velocity here: brainly.com/question/17228388

blondinia [14]2 years ago
8 0

Answer:

S=ut+12at2

Where, u is the initial velocity

a is the acceleration and,

t is the time taken.

For the right ball, the equation can be written as:

S=(0.3)t+12(−2)t2

On the other hand, for the left ball, we get the equation as:

4−S=(0.2)t+12(2)t2

After substituting the value of S from one equation of the other, we can find the value of time, t, easily as:

t=8s

Explanation:

so sorry if this is wrong

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Answer:

-10 m/s

Explanation:

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The net force on the smaller mass in the vertical direction (upward is positive) is

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If M = 1.0 kg and F = 60 N, then we end up with two equations with two unknowns,

60 N - T = (2.0 kg) a

T - (1.0 kg) (9.8 m/s²) = (1.0 kg) a

Eliminate a and solve for T :

(60 N - T) - 2 (T - (1.0 kg) (9.8 m/s²)) = (2.0 kg) a - 2 (1.0 kg) a

60 N - T - 2T + 19.6 N = (2.0 kg) a - (2.0 kg) a

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In 1898, the world land speed record was set by Gaston Chasseloup-Laubat driving a car named Jeantaud. His speed was 39.24 mph (
FromTheMoon [43]

Answer:

the acceleration a^{\to} = (0.0159 \ \ m/s^2 )i

Explanation:

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the initial speed v₁ = 0 m/s i.e starting from rest ; since the car accelerates at a distance Δx = 6 miles in order to teach that final speed v₂ of 63.15 km/h.

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