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3 years ago

Carbon becomes a part of the ground soil when:

1 answer:

6 0

I would say
A. Living things decay
Because when living things break down/decay, it becomes a nutrient for the soil like a fertilizer. B is wrong because although plants is a living thing, humans is also, but they don’t go through photosynthesis, which is transforming sunlight into food. C is wrong because runoff enters the nearby bodies of water, this is just water coming down (like raining, snowing, hailing) somewhere into the runoff to go into the nearby bodies of water and goes over the same water cycle over and over again. Although bacteria does convert carbon in the air (D) and form the plant host can use, but it’s part of the ground soil, so it’s not D.

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Calculate the average atomic mass for the following element given information about the relevant isotopes: (Isotope 1) Mass = 20

polet [3.4K]

Answer:

The average atomic mass of given element is 20.18 amu.

Explanation:

Given data:

Abundance of 1st isotope mass 20 amu = 90.92%

Abundance of 2nd isotope mass 21 amu = 0.257%

Abundance of 3rd isotope mass 22 amu = 8.82%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass = (90.92×20)+(0.257×21)+(8.82×22) /100

Average atomic mass = 1818.4 + 5.397 +194.04 / 100

Average atomic mass = 2017.819 / 100

Average atomic mass = 20.18 amu.

The average atomic mass of given element is 20.18 amu.

5 0

3 years ago

Of protons, neutrons, and electrons, the least massive particle is the electron.is it True or False

const2013 [10]

The least massive particle is the electron. Hence, the option true is correct.

<h3>What are subatomic particles?</h3>

Sub-atomic particles are tiny particles of matter that together constitute an atom. There are three subatomic particles, which are namely electrons, protons and neutrons.

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron).

Hence, the option true is correct.

Learn more about the subatomic particles here:

brainly.com/question/13303285

#SPJ1

5 0

2 years ago

What type of bond will be formed between Ar and Cu

Ronch [10]

It will be ionic because it’s a metal and a gas forming together

6 0

3 years ago

Scientists who always report their observations and results truthfully possess the attitude of

Firdavs [7]

The scientific method use, and thus going "for, the idea of following the ideal of scientific evidence.

4 0

3 years ago

A 36.165 mg36.165 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion an

erma4kov [3.2K]

Answer:

The empirical formula for the compound is C6H12SO2.

Explanation:

We'll begin by writing out what was given from the question. This is shown:

Let us consider the First experiment:

Mass of the compound = 36.165 mg

Mass of CO2 = 64.425 mg

Mass of H2O = 26.373 mg

Data obtained from the Second experiment:

Mass of compound = 47.029 mg

Mass of SO2 = 20.32 mg

Next, we'll determine the mass of C, H and S. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C in CO2 = 12/44 x 64.425 Mass of C = 17.57 mg

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H in H2O = 2/18 x 26.373

Mass of H = 2.93 mg

Molar Mass of SO2 = 32 + (16x2) = 64g/mol

Mass of S in SO2 = 32/64 x 20.32

Mass of S = 10.16 mg

At this stage, it is important we determine the percentage composition of C, H, S and O. This is illustrated below:

% of C = 17.57/36.165 x 100 = 48.58%

% of H = 2.93/36.165 x 100 = 8.10%

% of S = 10.16/47.029 x 100 = 21.60%

% of O = 100 - (48.58 + 8.1 + 21.6)

% of O = 21.72%

Now we can easily obtain the empirical formula for the compound by doing the following.

Step 1:

Divide by their molar mass

C = 48.58/12 = 4.0483

H = 8.10/1 = 8.1

S = 21.60/32 = 0.675

O = 21.72/16 = 1.3575

Step 2:

Divide by the smallest:

C = 4.0483/0.675 = 6

H = 8.1/0.675 = 12

S = 0.675/0.675 = 1

O = 1.3575/0.675 = 2

From the calculations made above, empirical formula for the compound is C6H12SO2

7 0

3 years ago