Number of moles = volume / (molar volume)
Molar volume at stp = 22.4 dm^3
Volume = no of moles × molar volume
= 0.987 × 22.4
= 22.1088 dm^3
= 22108.8 cm^3
Hope it helped!
Answer:
![AU^{3+} : [Rn] 5f^3](https://tex.z-dn.net/?f=AU%5E%7B3%2B%7D%20%3A%20%5BRn%5D%205f%5E3)
Explanation:
Writing electronic configuration of any element you should know atomic number of that element ,
and also electrons are filling according to their energy level and first electron is filled in the lower energy orbital
and it follows n+1 rule if n+1 is same for two orbital electron will go first in the lowest value of n.
writing electronic configuration of ion can be done like first for their neutral atom and then add or remove electron it will make things easy because there are also some eception case their you may do wrong.
![AU : [Rn] 5f^3 6d^1 7s^2](https://tex.z-dn.net/?f=AU%20%3A%20%5BRn%5D%205f%5E3%206d%5E1%207s%5E2)
remove three electron from outer most shell of AU
Answer : The number of moles of 
reacted was, 0.214 moles.
Explanation :
First we have to calculate the mole of 
gas.
Using ideal gas equation:
where,
P = Pressure of gas = 748 mmHg - 23.8 mHg = 724.2 mmHg = 0.953 atm (1 atm = 760 mmHg)
V = Volume of gas = 5.50 L
n = number of moles = ?
R = Gas constant = 
T = Temperature of gas = 
Putting values in above equation, we get:
Now we have to calculate the moles of
The balanced chemical reaction is:
From the balanced chemical reaction we conclude that,
As, 1 mole of gas produced from 1 mole of
So, 0.214 mole of gas produced from 0.214 mole of
Therefore, the number of moles of reacted was, 0.214 moles.
Answer:
NH₄⁺ (aq) + OH⁻ (aq)+ H⁺ (aq)+ Cl⁻ (aq) → NH₄⁺ (aq)+ Cl⁻ (aq)+ H₂O (l)
Explanation:
NH₄OH (l) + HCl (l) → NH₄Cl (aq) + H₂O (l)
This is called a <u>molecular equation</u> because <em>the formulas of the compounds are written as though all species existed as molecules or whole units</em>.
However, because both the acid and the base are strong electrolytes, they are completely ionized in solution. Therefore, the ionic equation is:
NH₄⁺ (aq) + OH⁻ (aq)+ H⁺ (aq)+ Cl⁻ (aq) → NH₄⁺ (aq)+ Cl⁻ (aq)+ H₂O (l)
In an aqueous solution of lithium chloride (LiCl), the ions present in solution are lithium cations (Li+) and chloride anions (Cl-), and the water molecules (H2O).
Lithium chloride is an ionic salt, and therefore, fully dissociates or ionizes upon dissolution in water. From the chemical formula of lithium chloride, we can say that 1 lithium ion (positively-charged) only needs 1 chloride ion (negatively charged) to form the salt. Thus, upon dissociation of 1 molecule of LiCl, only 1 lithium ion, and 1 chloride ion form.
Water is a molecule formed by covalent bonds and <u>generally</u>, does not dissociate to form ions. However, if we consider the very minor contribution of the dissociation of water, hydroxide (OH-) ions and hydronium (H3O+) ions will also be present. However for water, very few molecules, only 1 in 550 million, are dissociated at any given time. Thus, we can consider the presence of the OH- and H3O+ ions to be negligible and just identify the molecular undissociated form of water to be present.
