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Dmitry_Shevchenko [17]
2 years ago
8

Passive prostheses are:

Chemistry
2 answers:
Len [333]2 years ago
5 0

Passive prostheses are self-regulating, as shown in the first answer option.

We can arrive at this answer because:

  • Passive prostheses are devices used to replace parts of the body that were lost by an incident.
  • These prostheses are very useful to establish balance or the aesthetics of the body, but they have no articulations and no movement mechanism, being static.

This limitation allows passive prostheses not to need external regulation and to be self-regulated by fitting the body parts.

You can find more information about articulations and their effects on the link:

brainly.com/question/5847359?referrer=searchResults

soldier1979 [14.2K]2 years ago
4 0

Answer:

self-powered.

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A logical conclusion based on observations is called an inference.
Roman55 [17]
ANSWER: True
EXPLANATION: An inference is a logical conclusion based on observations.

Hope it helps u!
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3 years ago
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How many moles of atoms are in 6.00 g of 13C?
Lyrx [107]

Answer: 0.462 moles

Explanation: 13C indicates an isotope of carbon and its mass number is 13. It means the mass of 1 mol of 13C is 13 gram.

The question asks to calculate the number of atoms present in 6.00 grams of 13C.

To calculate the number of moles we divide the given grams by the mass of 1 mol of the element. The set could be shown easily using dimensional analysis as:

6.00gram(\frac{1mol}{13gram})

= 0.462 moles

So, there will be 0.462 moles of atoms in 6.00 grams of 13C.

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3 years ago
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In Thomson's plum pudding model the mass of the atom is in the A.electrons. B.matter between the electrons. C.nucleus. D.proton
balu736 [363]
A electrons is the best choice!
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Which types of reactions would result in the production of gas?
mylen [45]

Answer:

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3 years ago
Calculate the pH of the solution that results when 20 mL of 0.2M HCOOH is mixed with 25mL of 0.2M NaOH solution.(post-equivalenc
Paul [167]

The pH of the solution : 12

<h3>Further explanation</h3>

Reaction

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

mol HCOOH =

\tt 20~ml\times 0.2~M=4~mlmol

mol NaOH =

\tt 25~ml\times 0.2~M=5~mlmol

Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]

ICE method :

HCOOH    +     NaOH   ⇒     HCOONa   +   H₂O

4                          5

4                          4                     4                   4

0                          1                      1                    1

Concentration of [OH⁻] from NaOH :

\tt \dfrac{1~mlmol}{20+25~ml}=0.02

pOH=-log[OH⁻]

pOH=-log 10⁻²=2

pH+pOH=14

pH=14-2=12

3 0
3 years ago
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