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Sonja [21]
3 years ago
14

The device is a burner from an electric stove. It is used to transfer heat to a pot by A. Conduction B. Convection C. Radiation

D. Friction
Physics
2 answers:
OlgaM077 [116]3 years ago
4 0

<u>Answer:</u>

A device is a burner from an electric stove. Then the <em>conduction heat</em> is transferred to a pot.

Conduction heat is a method of heat transfer in which the the transfer is takes place by direct contact between objects. From the question , it is clear that, the burner from electric stove transfers energy to a bottom of the pot sitting on it.

Irina-Kira [14]3 years ago
3 0

I’m pretty positive that it’s A. Conduction. Just refer to the definition of it.

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if a moving object travels north for a distance of 105 m in 22 sec, what is it’s speed and velocity ?
artcher [175]

Answer:

Speed: 4.8 m/s

Velocity: 4.8 m/s north

Explanation:

Definitions:

- Speed is a scalar quantity, which is equal to the ratio between distance covered (d) and time taken (t):

s=\frac{d}{t}

- Velocity is a vector quantity, whose magnitude is equal to the ratio between the displacement of the object and the time taken:

v=\frac{disp.}{t}

And it also has a direction (the same as the displacement).

In this problem:

- The object travels a distance of

d = 105 m

In a time interval of

t = 22 s

So its speed is

s=\frac{105}{22}=4.8 m/s

- The displacement of the object is the same as the distance in this case, so still 105 m, covered in a time interval of 22 s; this means that the magnitude of the velocity is the same as the speed:

v=4.8 m/s

However, velocity is a vector quantity, so it also has a direction: and since the object has moved north, the direction of the velocity is north as well.

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4 0
3 years ago
A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg
slava [35]

Answer:

Explanation:

mass of first marble m_1=m=0.015\ kg

Initial velocity of the first marble u_1=22.5\ m/s

considering right side as positive

Mass of second marble

m_2=m=0.015\ kg\\u_2=-18\ cm/s

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. v_1=-18\ cm/s

considering v_2 be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

e=\frac{v_2-v_1}{u_1-u_2}

Putting values

1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy =0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J

Final kinetic energy=

0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J

6 0
3 years ago
A particle moves with a velocity    1 v 5j 3j 6k ms      under influence of a contact force  F 10i 10j 20k N.    
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Answer:

P = 200 W

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the job

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we substitute

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We apply this equation to our case where the velocity is

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and the force is

 F = (10i + 10j +20 k) N

we substitute in the power equation, remember that the scalar product of the unit vectors is

i.i = j.j = k.k = 1 and the other products are zero

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