Which of these is NOT a reason why the geocentric model of the solar system was once commonly accepted as the correct model?

A 397-N wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 25.

AleksAgata [21]

Answer:

h = 14.4 m

Explanation:

The height can be calculated by energy conservation:

$K_{r} + K_{t} - W = E_{p}$

<u>Where</u>:

W: is the work

$E_{p}$ : is the potential energy

$K_{r}$ : is the rotational kinetic energy

$K_{t}$ : is the transitional kinetic energy

Initially, the wheel has rotational kinetic energy and translational kinetic energy, and then when stops it has potential energy.

$K_{r} + K_{t} - W = E_{p}$

$\frac{1}{2}I\omega_{0}^{2} + \frac{1}{2}mv^{2} - W = mgh$

<u>Where</u>:

I: is the moment of inertia = 0.800 mr²

ω₀: is the angular speed = 25.0 rad/s

m: is the mass = P/g = 397 N/9.81 m*s⁻² = 40.5 kg

v: is the tangential speed = ω₀r²

Now, by solving the above equation for h we have:

$h = \frac{\frac{1}{2}(I\omega_{0}^{2} + mv^{2}) - W}{mg}$

$h = \frac{\frac{1}{2}(I\omega_{0}^{2} + m(\omega_{0}*r)^{2}) - W}{mg}$

$h = \frac{\frac{1}{2}(0.800*40.5 kg*(0.600 m)^{2}*(25.0 rad/s)^{2} + 40.5 kg*(25.0 rad/s*0.600 m)^{2}) - 2500 J}{40.5 kg*9.81 m/s^{2}} = 14.4 m$

Therefore, the height is 14.4 m.

I hope it helps you!

4 0

3 years ago

Calculate the initial speed of a box which slides on a horizontal floor surface and comes to rest after sliding 2 s. The coeffic

NARA [144]

A box sliding on a horizontal floor surface starts out moving at 4.9 m/s and stops after 2 seconds. The surface and the box have a kinetic friction has friction coefficient of 0.25 (g=9.8 ms-2).

The speed of an object at the start of a measurement, or an initial state, is known as the initial speed. The ratio of distance travelled to travel time, also known as the average speed, is the sum of the initial and final speeds. The difference between initial and ending speeds is the speed change. A force that acts between moving surfaces is referred to as kinetic friction. A force acting in opposition to the direction of a moving body on the surface is felt.

Interval (t) equals 2 seconds

Kinetic friction coefficient is 0.25.

gravity-induced acceleration (g) = 9.8 m/s2.

Coming to a stop at a final velocity of 0 m/s.

Regular force equals mg

Kinetic friction force is given by = k.

N = μkmg

I = (delta P) (delta P)

Vo = (0.25)(9.8)(2) (2)

Vo = 4.9m/s

Learn more about kinetic friction here

brainly.com/question/17237604

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3 0

1 year ago

A. In the building there are 133 steps from the ground floor to the sixth floor.

faust18 [17]

(a) The work done by the person is 18.83465 kJ.

(b) The average power performed by the person during the walk is 51.4 W.

(c) The amount of food calories burnt is 4.5 Cal.

<h3>Work done by the person</h3>

The work done by the person is calculated as follows;

W = Fd

W = mgh

W = (89.2 x 9.8) x (0.162 x 133)

W = 18,834.65 J

W = 18.83465 kJ

<h3>Average power of the person</h3>

P = Fv

where;

v is velocity

v = (d)/t

v = (133 x 0.162)/(6 x 60 + 6)

v = (133 x 0.162)/(366)

v = 0.0588 m/s

P = (89.2 x 9.8) x 0.0588

P = 51.4 W

<h3>Amount of food calories burnt</h3>

4.1868 kJ = 1 Cal

18.83465 kJ = ?

= 4.5 Cal

Learn more about work done here: brainly.com/question/8119756

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7 0

2 years ago

What is the difference between the velocity and the speed of an object?

timurjin [86]

Answer:

Velocity has a direction associated with it, while speed has no specific direction.

Explanation:

Velocity is a vector, while speed is a scalar.

3 0

3 years ago

A 4.80 Kg watermelon is dropped from rest from the roof of an 18.0 m building. Calculate the work done by gravity on the waterme

Nonamiya [84]

Answer:

Work, W = 846.72 Joules

Explanation:

Given that,

Mass of the watermelon, m = 4.8 kg

It is dropped from rest from the roof of 18 m building. We need to find the work done by the gravity on the watermelon from the roof to the ground. It is same as gravitational potential energy i.e.

W = mgh

$W=4.8\ kg\times 9.8\ m/s^2\times 18\ m$

W = 846.72 Joules

So, the work done by the gravity on the watermelon is 846.72 Joules. Hence, this is the required solution.

7 0

3 years ago