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marishachu [46]
3 years ago
10

An air compressor takes normal air and pushes more and more of it in a rigid steel tank. The number of gas particles in the tank

is increased. What happens to the temperature as more and more air is pushed into a tank which does not change size?
A. It increases


B. It stays the same


C. It decreases
Physics
1 answer:
erik [133]3 years ago
3 0

Answer:

C. It decreases

Explanation:

The pressure law states that for a constant volume of gas in a sealed container the temperature of the gas is directly proportional to its pressure. This can be easily understood by visualizing the particles of gas in the container moving with a greater energy when the temperature is increased.

A common example is cooking gas when refilled, there is a perceptible change in the temperature of the cylinder.

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If a 51kg snowboarder falls of a cliff, and is falling 15 m/s when they impact the snow, what is the average force of the snow o
storchak [24]

Answer:

Average force is F = mass times change in V/ change in time so..

1 366.07143 N

Explanation:

51 kg x 15 m/s / 0.56

1 366.07143 m kg / s

1 366.07143 N

1 kilogram 1 meter per second per second = 1 N

5 0
3 years ago
Why the specific heat capacity of the sun remain constant<br><br>​
gayaneshka [121]
The heat remains constant because there’s nothing to cool it down
7 0
3 years ago
A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia
Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

6 0
3 years ago
A 60 kg skier starts from rest at the top of a frictionless slope of height of 35 meters. The velocity at the bottom is v. If a
Solnce55 [7]

Answer:

Explanation:

Speed of skier without parachute

= √ 2gh

= √ 2 x 9.8 x 35

= 26.2 m / s

Speed of skier with parachute

net force downwards

mg - 200

= 60 x 9.8 -200

= 388 N

acceleration = 388 / 60

a = 6.47 m / s

v = √ 2ah

= √ 2 x 6.47 x 35

= 21.28 m / s

8 0
2 years ago
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The temperature inside my refrigerator is about 4 degrees C. If I place a balloon in my fridge that initially has a temperature
maksim [4K]

v

Convert the given temperatures from celsius to kelvin since we are dealing with gas.

To convert to kelvin, add 273.15 to the temperature in celsius.

T1 = 22 + 273.15 = 295.15 k

T2 = 4 + 273.15 = 277.15 k

V1 = 0.5 L

Let's find the final volume (V2).

To solve for V2 apply Charles Law formula below:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

5 0
1 year ago
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