The frequency shift your FuzzFoiler 2000 radar detector will see is 10.6 GHz.
<h3>Doppler effect</h3>
The doppler effect show the frequency shift of a source of sound relative to an observer depending on their relative motion.
The frequency shift f' = f(v ± v')/(v ± v") where
- f = frequency of source = 9.50 GHz,
- v = speed of sound = 330 m/s,
- v' = speed of detector = speed of car = 37.9 m/s and
- v" = speed of source = 0 m/s (since the highway patrol car is stationary)
Since the detector (our car) approaches the source (the radar gun), we use the positive sign in the numerator and a negative in the denominator
So, f' = f(v + v')/(v - v")
Since v" = 0, we have
f' = f(v + v')/(v - 0)
<h3>The frequency shift</h3>
f' = f(v + v')/v
Substituting the values of the variables into the equation, we have
f' = 9.50 GHz(330 m/s + 37.9 m/s)/330 m/s
f' = 9.50 GHz(367.9 m/s)/330 m/s
f' = 9.50 Ghz × 1.115
f' = 10.6 GHz
So, the frequency shift your FuzzFoiler 2000 radar detector will see is 10.6 GHz.
Learn more about Doppler effect here:
brainly.com/question/11419686
