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TEA [102]
3 years ago
11

The state highway patrol radar guns use a frequency of 9.50 GHz. If you're approaching a speed trap driving 37.9 m/s, what frequ

ency shift will your FuzzFoiler 2000 radar detector see
Physics
1 answer:
Grace [21]3 years ago
6 0

The frequency shift your FuzzFoiler 2000 radar detector will see is 10.6 GHz.

<h3>Doppler effect</h3>

The doppler effect show the frequency shift of a source of sound relative to an observer depending on their relative motion.

The frequency shift f' = f(v ± v')/(v ± v") where

  • f = frequency of source = 9.50 GHz,
  • v = speed of sound = 330 m/s,
  • v' = speed of detector = speed of car = 37.9 m/s and
  • v" = speed of source = 0 m/s (since the highway patrol car is stationary)

Since the detector (our car) approaches the source (the radar gun), we use the positive sign in the numerator and a negative in the denominator

So, f' = f(v + v')/(v - v")

Since v" = 0, we have

f' = f(v + v')/(v - 0)

<h3>The frequency shift</h3>

f' = f(v + v')/v

Substituting the values of the variables into the equation, we have

f' = 9.50 GHz(330 m/s + 37.9 m/s)/330 m/s

f' = 9.50 GHz(367.9 m/s)/330 m/s

f' = 9.50 Ghz × 1.115

f' = 10.6 GHz

So, the frequency shift your FuzzFoiler 2000 radar detector will see is 10.6 GHz.

Learn more about Doppler effect here:

brainly.com/question/11419686

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<span>Th find the average speed of a trip we need to dived the total distance by the total time. Let's find the total distance d. d = (300 mi/h)(2.00 h) + 750 miles d = 600 miles + 750 miles d = 1350 miles The total distance is 1350 miles Let's find the total time t. t = 2.00 hours + (750 mi / 250 mi/h) t = 2.00 hours + 3.00 hours t = 5.00 hours The total time of the trip is 5.00 hours. We can find the average speed. d / t = 1350 miles / 5.00 hours d / t = 270 miles/ hour The average speed of the trip is 270 mi/h (Note that the direction does not matter when we find the average speed.)</span>
6 0
4 years ago
Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.9 m tall window in 0.134 sec. From how high above th
timama [110]

Answer:

Explanation:

Given

length of window h=2.9\ m

time Frame for which rock can be seen is \Delta t=0.134\ s

Suppose h is height above which rock is dropped

Time taken to cover h+2.9 is t_1

so using equation of motion

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

time taken to travel h  is

h=0+0.5\times g\times (t_2)^2---2

Subtract 1 and 2 we get

2.9=0.5g(t_1^2-t_2^2)

5.8=g(t_1+t_2)(t_1-t_2))

and from equation t_1-t_2=0.134\ s

so t_1+t_2=\frac{5.8}{9.8\times 0.134}

t_1+t_2=4.416\ s

and t_1=t_2+\Delta t

so t_2+\Delta t+t_2=4.416

2t_2+0.134=4.416

t_2=0.5\times 4.282

t_2=2.141\ s

substitute the value of t_2 in equation 2

h=0.5\times 9.8\times (2.141)^2

h=22.46\ m

                                                     

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3 years ago
A laptop can convert 400J of electrical energy into a 240J of light and sound. What is the efficiency? Where does the rest of th
Blababa [14]
Efficiency = (Wanted) energy out ÷ energy in × 100

Energy in = 400J
Wanted Energy out = 240J

Energy cannot be used up, only transferred, so the remaining energy is most likely to be transferred into unwanted energy (loss of energy) such as heat energy.

Efficiency = 240 ÷ 400 × 100
Efficiency = 0.6 × 100
Efficiency = 60%
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How does being on the moon effect gravitational field strength
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Your being on the moon has no effect on the moon's
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and anything else are only 16% as great as the same forces are on
Earth.

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