Question

Pure silver has a brilliant white metallic luster. How many moles of silver, Ag, are in 7.54 × 1023 atoms of silver?

Answer 1

The number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles

From the question,

We are to determine the number of moles of silver, Ag, that are present in 7.54 × 10²³ atoms of silver

From the formula

$Number\ of\ moles =\frac{Number\ of\ atoms}{Avogadro's\ constant}$

Avogadro's  constant = 6.022 × 10²³  atoms mol⁻¹

and

From the given information

Number of silver atoms = 7.54 × 10²³ atoms

Putting the parameters into the formula, we get

Number of moles of silver present = $\frac{7.54\times 10^{23} }{6.022\times 10^{23}}$

Number of moles of silver present = 1.2520757 moles

Number of moles of silver present ≅ 1.25 moles

Hence, the number of moles of silver, Ag, that are in 7.54 × 10²³ atoms of silver is 1.25 moles

Learn more on calculating number of moles here: brainly.com/question/15839520