The greater the change in velocity, or speed.
Answer:
W = 1.8 J
Explanation:
The amount of work required to move the given charges can be found by using the following formula:
where,
W = Work done = ?
k = Colomb's constant = 9 x 10⁹ Nm²/C²
q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ C
q₂ = magnitude of second charge = 4 μC = 4 x 10⁻⁶ C
Δr = change in distance = 18 cm - 6 cm = 12 cm = 0.12 m
Therefore,
<u>W = 1.8 J</u>
A distance of d is covered with 53 mile/hr initially.
Time taken to cover this distance t1 = d/53 hour
Next distance of d is covered with x mile hours.
Time taken to cover this distance t2 = d/x hours.
We have average speed = 26.5 mile / hour
= Total distance traveled/ total time taken
=
Answer:
(a) 0.277 m
(b) 0.553 m
Explanation:
(a) For the closed cylinder,
Applying,
f' = v/4l............. Equation 1
Where f' = fundamental frequency, v = velocity of sound, l = lenght of the cylinder
make l the subject of the equation
l = v/4f'............. Equation 2
From the question,
Given: v = 343 m/s, f' = 310 Hz
Substitute these values into equation 2
l = 343/(4×310)
l = 0.277 m
(b) For the open cylinder,
f' = v/2l
l = v/2f'................ Equation 3
Substitute into equation 3
l = 343/(2×310)
l = 0.553 m
Answer:
The Questions are
a. Calculate the x-component of the electric field, in newtons per coulomb
b. Calculate the y-component of the electric field, in newtons per coulomb
c. Calculate the z-component of the electric field, in newtons per coulomb
d. Calculate the magnitude of the electric field, in newtons per coulomb.
Explanation:
Given that,
Φx= 85 N•m2/C. X direction
Φy= -85 N•m2/C. Y direction
Φz = 0. Z direction
Radius of loop =3cm=0.03m
Surface area of the circle is πr²
A=22/7×0.03²
A=0.00283m²
Flux is given as Φ=EA
a. Φx=ExA
Ex=Φx/A
Ex=85/0.00283
Ex=30035.33N/C
b. Ey=Φy/A
Ey=-85/0.00283
Ey=-30035.33N/C.
c. Ez=Φz/A
Ez, =0/A
Ez=0N/C
d. Magnitude of E.
E=√Ex²+Ey²+Ez²
E=√(30035.33)²+(-30035.33)²
E=42476.38N/C.