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vaieri [72.5K]
3 years ago
9

A car has an engine which delivers a constant power. It accelerates from rest at time t = 0, and at t = t0 its acceleration is a

0. What is its acceleration at t = 2t0? Ignore energy loss due to friction. ...?
Physics
1 answer:
olga2289 [7]3 years ago
7 0
Here is the answer of the given problem above.
Use this formula: <span>P = FV = ma*at = ma^2 t
</span><span>Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
</span>The <span>answer would be a0/sqrt(2).
Hope this answers your question. Thanks for posting.
</span>
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A child in a tree house uses a rope attached to a basket to lift a 24 N dog upward through a distance of 4.9 m into the house.
jenyasd209 [6]
<h3>Answer:</h3>

117.6 Joules

<h3>Explanation:</h3>

<u>We are given;</u>

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We are required to calculate the work done

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In this case;

Force applied is equivalent to the weight of the dog.

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264Ns

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Inputting the parameters:

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