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3 years ago

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How does an insulator stop the flow of an electric current? A. Insulators have too many electrons. B. Insulators have a positive

charge so they absorb electrons. C. Electrons in an insulator do not move readily. D. Insulators convert electric energy to other forms of energy.

2 answers:

Olenka [21]3 years ago

5 0

<span>The question is how does an insulator stops the flow of electricity. The correct option is C. This is because insulators are objects whose internal electric charges do not flow freely. They impede the flow of electrons from one atom to another atom, thus restricting the flow of electricity. Insulators are electrically inactive and the are used to stop the flow of electric current. </span>

miskamm [114]3 years ago

4 0

Answer:

I took the test the correct answer is C.

Explanation:

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hram777 [196]

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3 years ago

A cube 6.0 cm on each side is made of a metal alloy. After you drill a cylindrical hole 2.0 cm in diameter all the way through a

Crank

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and the geometric relationships that allow us to find the volume of the figures presented.

For the particular case of the Cube with equal sides its volume is determined by

$V_c = l^3$

$V_c = 6^3 = 216cm^3$

In the case of perforated material we have that its volume is given according to the cylindrical geometry, that is to say

$V_d = \pi r^2*l$

$V_d = \pi (\frac{2}{2})^2*6$

$V_d = 6\pi cm^3$

In this way the net volume would be

$\Delta V = V_c-V_d$

$\Delta V = 216cm^3-6\pi cm^3$

$\Delta V = 197.15cm^3 = 197.15*10^{-6}m^3$

We need to find the mass, but we have the Weight and Gravity so from Newton's second Law

$F= mg$

$m = \frac{F}{g}$

$m = \frac{6.6}{9.8}$

$m = 0.673kg$

PART A) From the relation of density as a unit of mass and volume we have to

$\rho = \frac{m}{V}$

$\rho = \frac{0.673}{197.15*10^{-6}}$

$\rho = 3413.64kg/m^3$

PART B) To find the weight of the cube then we apply the ratio of

$W = mg$

$W = V\rho g$

$W = (216*10^{-6})(3413.64)(9.8)$

$W = 7.22N$

3 0

3 years ago

A 5.00X10^5 kg rocket is accelerating straight up. Its engines produce 1.250X10^7 N of thrust, and air resistance is 4.50X10^6 N

katrin [286]

<span>6.20 m/s^2 The rocket is being accelerated towards the earth by gravity which has a value of 9.8 m/s^2. Given the total mass of the rocket, the gravitational drag will be 9.8 m/s^2 * 5.00 x 10^5 kg = 4.9 x 10^6 kg m/s^2 = 4.9 x 10^6 N Add in the atmospheric drag and you get 4.90 x 10^6 N + 4.50 x 10^6 N = 9.4 x 10^6 N Now subtract that total drag from the thrust available. 1.250 x 10^7 - 9.4 x 10^6 = 12.50 x 10^6 - 9.4 x 10^6 = 3.10 x 10^6 N So we have an effective thrust of 3.10 x 10^6 N working against a mass of 5.00 x 10^5 kg. We also have N which is (kg m)/s^2 and kg. The unit we wish to end up with is m/s^2 so that indicates we need to divide the thrust by the mass. So 3.10 x 10^6 (kg m)/s^2 / 5.00 x 10^5 kg = 0.62 x 10^1 m/s^2 = 6.2 m/s^2 Since we have only 3 significant figures in our data, the answer is 6.20 m/s^2</span>

8 0

3 years ago

A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine

bixtya [17]

125 W is the power output of this machine.

Answer:

Explanation:

Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.

So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is

$Power = \frac{Work done}{Time}$

As Work done = Force acting on the machine × Displacement

So $Power = \frac{(Force * Displacement)}{Time}$

Power = $\frac{(100*5)}{4}$ =125 W

So, 125 W is the power output of this machine.

6 0

3 years ago

How much time elapses before the two kittens collide

geniusboy [140]

Answer:

6.8 s

Explanation:

Let's say the west end of the field is position 0 m and the east end of the field is position 250 m.

The position of kitten A is:

x = 0 + 25 t

And the position of kitten B is:

x = 250 - 12 t

The kittens collide when they have the same position:

25 t = 250 - 12 t

37 t = 250

t ≈ 6.8 s

3 0

3 years ago