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Phoenix [80]
3 years ago
9

How many molecules are in 4.08 moles of CCL4

Chemistry
1 answer:
Likurg_2 [28]3 years ago
5 0
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5. Which of the following elements will have a charge of 4+ or 4- as an ion?
hjlf

Answer:

The answer would either be Carbon or Silicon.

Explanation:

8 0
3 years ago
“Enter the conjugate acids of no2- and no3-“
Rainbow [258]

Answer:

nitrit,nitrat

4 0
3 years ago
What was done to the linear parent function, f(x) = x, to get the function<br>g(x) = 1/6 x​
s2008m [1.1K]

Answer:

Vertically Shrunk by a factor of 1/6

Explanation:

Parent Formula: f(x) = a(bx - c) + d

<em>a</em> - vertical shrink/stretch and x-reflections

<em>b</em> - horizontal shrink/stretch and y-reflections

<em>c</em> - horizontal movement left/right

<em>d</em> - vertical movement up/down

Since we are only modifying <em>a</em>, we are dealing with vertical shrink/stretch:

Since a < 1 (1/6 < 1), we are dealing with a vertical shrink of 1/6.

Since a > 0 (1/6 > 0), we do not have a reflection over the x-axis.

7 0
3 years ago
The state of matter in which a material has a definite shape and a definite volume is the _____ state.
Scilla [17]

Answer:

solid

Explanation:

in the solid state the material will has a fixed shape and volume whatever the container that contains it

where in liquid the shape will be different depending on the container

and in gas state the shape and volume are not definite

3 0
3 years ago
When a compound containing cesium ions is heated in a Bunsen burner flame, photons with an energy of 4.30 x 10-19 J are emitted.
inessss [21]

<u>Answer:</u> The wavelength of the flame is 462 nm and color of cesium flame is blue.

<u>Explanation:</u>

To calculate the wavelength, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = Energy of 1 photon = 4.30\times 10^{-19}J

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = ?

Putting values in above equation, we get:

4.30\times 10^{-19}=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{\lambda }\\\\\lambda=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{4.30\times 10^{-19}}=4.62\times 10^{-7}m=462nm

The range of wavelength of blue light lies in range of 500 nm - 435 nm

The calculated wavelength lies in the above range. So, the color of the cesium flame is 462 nm

Hence, the wavelength of the flame is 462 nm and color of cesium flame is blue.

6 0
3 years ago
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