Answer:
O-H bond
Explanation:
Let us work out the electronegativity difference between the elements in each bond in order to decide which of them is most polar.
For the C-O bond
2.55 - 2.2 =0.35
For the F-F bond
3.98 - 3.98 = 0
For the O-H bond
3.44 - 2.2 = 1.24
For the N-H bond
3.04 - 2.2 = 0.84
The O-H bond has the highest electronegativity difference, hence it is he most polar bond.
Explanation:
When an atom's outermost orbital gains or loses electrons (also known as valence electrons), the atom forms an ion. An ion with more protons than electrons carries a net positive charge and is called a cation. An ion with more electrons than protons carries a net negative charge and is called an anion
Molar mass NaHCO₃ = 23 + 1 + 12 + 16 x 3 = 84 g/mol
1 mole ---------- 84 g
? mole ---------- 110 g
moles NaHCO₃ = 110 . 1 / 84
moles NaHCO₃ = 110 / 84
= 1.309 moles
hope this helps!
Explanation:
<u>Polar covalent bonding is the type of the chemical bond in which the pair of the electrons is unequally shared between the two atoms.</u> As a result, the atom with higher value of electronegativity acquires a slightly negative charge and the atom with lower value of electronegativity acquires a slightly positive charge.
In the molecule of
, the bond which is closest to ionic end of bond spectrum is <u>N-H bond</u> because the nitrogen atom is more electronegative than hydrogen and is ionic in nature.
In the molecule of
, the bond which is closest to ionic end of bond spectrum is <u>no one</u> because there is not much difference between carbon and hydrogen for the bond to be said as ionic.
In the molecule of
, the bond which is closest to ionic end of bond spectrum is <u>O-H bond</u> because the oxygen atom is more electronegative than hydrogen and is ionic in nature.