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Assoli18 [71]
3 years ago
14

Which is true regarding the penetrating power of radiation? (2 points) Select one:

Physics
1 answer:
Monica [59]3 years ago
3 0

Answer:d

Explanation:

Alpha particles are heaviest among alpha, beta and gamma so they have least amount of Penetration compared to both.

Gamma Particles are lightest among three so they can Penetrate most .

The order of Penetration is given by

Alpha< Beta < Gamma              

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When a satellite orbits the earth?
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What kind of question is this lol
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2 years ago
The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles
tamaranim1 [39]

Answer:

A: 5.67*10^-5 N

B: 3.49*10^-5 N

C: -9.16*10^-5 N

Explanation:

\\A\\F_{A} = F_{BA} + F_{CA} =G*\frac{m_{b}*m_{a}}{r^2_{AB}} + G*\frac{m_{c}*m_{a}}{r^2_{AC}} \\\\= (6.67*10^(-11))*(\frac{363*517}{0.5^2} + \frac{154*363}{0.75^2})\\\\= 5.67*10^-5 N \\\\B\\\\F_{B} = -F_{BA} + F_{CB} =-G*\frac{m_{b}*m_{a}}{r^2_{AB}} + G*\frac{m_{c}*m_{b}}{r^2_{BC}} \\\\= (6.67*10^(-11))*(-\frac{517*363}{0.5^2} + \frac{517*154}{0.25^2})\\\\= 3.49*10^-5\\\\

F_{C} = -F_{CA} - F_{CB} =-G*\frac{m_{b}*m_{c}}{r^2_{BC}} - G*\frac{m_{c}*m_{a}}{r^2_{AC}} \\\\= (6.67*10^(-11))*(-\frac{517*154}{0.25^2} - \frac{154*363}{0.75^2})\\\\= -9.16*10^-5

7 0
3 years ago
Halving the distance (i.e., decreasing by a factor of two) between two charged objects will cause the electrical force between t
Tcecarenko [31]

Explanation:

Below is an attachment containing the solution.

7 0
2 years ago
A horse began running due east and covered 25 km in 4.0 hr. What is the average velocity of the horse?
Darina [25.2K]
<span>B) 6.25 km/hr due east </span>
3 0
3 years ago
Read 2 more answers
As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 2.91 back-and-forth cy
Lapatulllka [165]

Answer:

Wavelength, \lambda=0.011\ m

Explanation:

Given that,

Number of cycles in a spiral spring is 2.91 in every 3.67 s

The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s

To find,

Wavelength

Solution,

Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,

f=\dfrac{2.91}{3.67}=0.79\ Hz

The wavelength of a wave is given by :

\lambda=\dfrac{v}{f}

\lambda=\dfrac{0.00925\ m/s}{0.79\ Hz}

\lambda=0.011\ m

So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.

8 0
2 years ago
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