two point charges are placed on x-axis a 2×10 coulomb charge at x=10cm and -1×10-6 coulomb at x=40cm calculate potential at poin
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Answer:
Explanation:
Given that :
The current I = 8.6 A
The length vector L = 2.3 m i
The force vector is = -2.0 j N
When L = 2.3 m i ; the
Force vector F = (2.0 i - 4.8 k) N
Compute the components of the magnetic field as follows:
Replacing 8.6 A for I ; -2.0 j N for F & 2.3 m i for L
However in y direction ; we have :
Hence, the component of magnetic field is as follows: