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3 years ago

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two point charges are placed on x-axis a 2×10 coulomb charge at x=10cm and -1×10-6 coulomb at x=40cm calculate potential at poin

t x=100cm

1 answer:

ryzh [129]3 years ago

5 0

Answer:

hshdjdjdjdb

Explanation:

help me lol

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A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. What is the h

dybincka [34]

Given,

A player kicks a soccer hits at an angle of 30° at a speed of 26 m/s

We can resolute the trajectory of soccer into horizontal and vertical components.(Please see the attached file)

We can have,

Horizontal velocity component of ball= 26cos(30°) = 26×(√3÷2) = 22.51 m/s

And vertical velocity component of ball = 26sin(26°) = 26×(1÷2) = 13 m/s

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Larry drops a 5kg ball off of a building. The ball hits the ground 4.7s later. How tall is the building?

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Explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 4.7 s

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Δy = v₀ t + ½ at²

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A 15g football was kicked to an acceleration of 55m/s2. What was the force applied to it? 40N 3.7N 825N

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f =ma = 0.015 * 55 = 0.825 N

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A man works on a striaght road from his home to market 2.5km away dwith a speed of 5km/h.Finding the market closed, he instantly

umka21 [38]

Answer:

5.625km/h

Explanation:

We are given that

Distance between home and market, d=2.5 km

Speed, v1=5km/h

Speed, v2=7.5 km/h

We have to find the average speed of the man over the interval of time 0 to 40min.

Time, $t=\frac{distance}{speed}$

Using the formula

$t_1=\frac{2.5}{5}=0.5 h=0.5\times 60=30 min$

1 hour =60 min

$t_2=\frac{2.5}{7.5}=\frac{1}{3}hour=\frac{60}{3}=20min$

Distance traveled by man in 10 min with speed 7.5 km/h= $\frac{2.5}{20}\times 10=2.5/2km$

Therefore,

Total distance covered=2.5+2.5/2=3.75 km

Time=40 min=40/60=2/3 hour

Average speed= $\frac{total\;distance}{total\;time}$

Average speed= $\frac{3.75}{2/3}=5.625km/h$

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