Since a right triangle has special rules to it such that the hypotenuse squared equals the sum of the squares of the other 2 sides. In other words, if the hypotenuse = c, and the 2 smaller sides are a and b, then:

Solving for c (hypotenuse), we get:

Therefore c is the root of the square of the other sides. So by having root18, it's like saying:

Getting rid of the square root, so sides a and b must have their squares total 18:
the only squares < 18 are: 16 (4×4), 9 (3×3), 4 (2×2), and 1 (1×1)
of those above added in any order of two of them, only 16+4



I HOPE THAT IS ALONG THE LINE THAT WAS ASKED FOR!!! :-D
Answer:
a) y = |x/2 -2| +4
b) y = |x/2 -2| +2
c) y = |(x+1)/2 -2| +3
d) y = |(x-1)/2 -2| +3
Step-by-step explanation:
To translate the function f(x) by (h, k) in the (right, up) direction, you transform it to ...
g(x) = f(x -h) +k
<u>a) one unit up</u>
Add 1 to the function value.

<u>b) one unit down</u>
Subtract 1 from the function value.

<u>c) one unit left</u>
Replace x with x-(-1).

<u>d) one unit right</u>
Replace x with x-1.

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2/3 + 5/6
= 4/6 + 5/6
= 9/6
= 3/2
A. 3/2
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