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crimeas [40]
2 years ago
15

Acid rain is a term that refers to a mixture of wet and dry deposited material from the atmosphere containing higher than normal

amounts of nitric and sulfuric acids. Causes of acid rain include natural sources and man-made sources, mostly from the emissions of fossil fuel combustion, sulfur dioxide and nitrogen oxides. What is one natural source for these emissions contributing to acid rain
Chemistry
1 answer:
sattari [20]2 years ago
3 0

Answer: Volcanic Eruptions

Explanation:

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loris [4]
Organ is the answer
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3 years ago
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Rewrite this measurement with a simpler unit, if possible. <br> 8.3 kg•m^2/ s^2
Feliz [49]

Answer: 8.3 J

Explanation:

We have the following measurement:

8.3 \frac{kg m^{2}}{s^{2}}

Rearranging the units:

8.3 \frac{kg m}{s^{2}}m

Since 1 Newton is 1 N=1 \frac{kg m}{s^{2}}:

8.3 Nm

Since 1 Joule is 1 J=1 Nm:

8.3 J This is the simplest form possible

7 0
3 years ago
For each of the salts below, match the salts that can be compared directly, using Ksp values, to estimate solubilities.
Anni [7]

Answer:

1 - Salts required  that can be compared directly, using Ksp values, to estimate solubilities for copper (II) sulfide are - CaSO_3 (Option b) ,BaCrO_4 (Option c) and CaS (Option d)

2 - Salts  that can be compared directly, using Ksp values, to estimate solubilities for zinc hydroxide are - Mg(OH)_2 (Option a)

Explanation:

K_s_p values can be used to compare the solubility of salts that produce ions in a 1:1 ratio.

  1. CuS {copper (II)sulfide} dissociates with ions in ratio 1:1 .

Because the salts CaSO_3 , BaCrO_4 and CaS  have a 1:1 ion ratio, the solubilities of options b, c, and d can be compared to salt 1.

K_s_p Values can be used to compare the solubility of salts that produce ions in a 1:2 or 2:1 ratio.

  2. Zn(OH)_2 dissociates into ions in ratio 1:2 .

Because the ions in the salt Mg(OH)_2 are in a 1:2 ratio, the solubility of salt 2 can be compared to that of salt 'a'.

Hence , Salt 1 is matched with options b , c , d.

              Salt 2 is matched with option a.

4 0
3 years ago
What is the volume in L of 3.8 kg of this liquid?
DedPeter [7]
1L ------------ 1 kg
? ------------- 3.8 kg

3.8 x 1 / 1

= 3.8 L
4 0
3 years ago
What is the molarity of 4.0 moles NaCI dissolved in 2.0 L of solution
Hunter-Best [27]

Answer:

What is the molarity of a solution containing 5.00 moles of kcl in 2.00L of solution? Molarity= moles of solute/volume of solution in litre , so the problem looks like this : 7/. 569 , which is equivalent to 12.302 M .

3 0
3 years ago
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