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zvonat [6]
2 years ago
9

A 0.5 kg rock is thrown straight downward off a cliff. If the rock only experience a gravitation force for 4.3 seconds, and ends

with a downward velocity of 46.1 m/s, what was rock initial velocity? What is the gravitational force?
Physics
1 answer:
pogonyaev2 years ago
3 0

Answer:Answer:

See diagram for answers. The force and acceleration vectors are directed inwards towards the center of the circle and the velocity vector is directed tangent to the circle.

Explanation:

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A spring with a force constant of 5.3 n/m has a relaxed length of 2.60 m. when a mass is attached to the end of the spring and a
olganol [36]
This is the equation for elastic potential energy, where U is potential energy, x is the displacement of the end of the spring, and k is the spring constant. 
<span> U = (1/2)kx^2 
</span><span> U = (1/2)(5.3)(3.62-2.60)^2 
</span> U = <span> <span>2.75706 </span></span>J
6 0
3 years ago
Which location on the map above is a source of North Atlantic deep water?
bija089 [108]
The answer might be C ? hope it's right
4 0
3 years ago
Calculate the net force and the acceleration on the block
Darina [25.2K]

Answer:

Net Force = 10N

Acceleration = 2m/s^2

Explanation:

calculate the net force and the acceleration on the block

Net force on the block F = mass * acceleration

Net force acting in the positive direction = 4N + 6N = 10N

Mass = 5kg

According to newton's second law;

a = F/m

a = 10N/5

a = 2m/s^2

hence the acceleration on the block is 2m/s^2

7 0
3 years ago
The Huka Falls on the Waikato River is one of New Zealand's most visited natural tourist attractions. On average, the river has
OverLord2011 [107]

Answer:

(a) V = 0.75 m/s

(b) V = 0.125 m/s

Explanation:

The speed of the flow of the river can be given by following formula:

V = Q/A

V = Q/w d

where,

V = Speed of Flow of River

Q = Volume Flow Rate of River

w = width of river

d = depth of river

A = Area of Cross-Section of River = w d

(a)

Here,

Q = (300,000 L/s)(0.001 m³/1 L) = 300 m³/s

w = 20 m

d = 20 m

Therefore,

V = (300 m³/s)/(20 m)(20 m)

<u>V = 0.75 m/s</u>

<u></u>

(b)

Here,

Q = (300,000 L/s)(0.001 m³/1 L) = 300 m³/s

w = 60 m

d = 40 m

Therefore,

V = (300 m³/s)/(60 m)(40 m)

<u>V = 0.125 m/s</u>

8 0
3 years ago
si tienes 2 circuitos uno en serie y otro en paralelo con el mismo valor en sus resistencias, para cuál circuito la resistencia
Novosadov [1.4K]

Answer:

circuito paralelo

Explanation:

Siempre el circuito en paralelo dara una resistencia menor. Recuerda que las resistencias se suman en el circuito en serie, an cambio en el circuito en paralelo, la corriente se bifurca de manera de circular con mayor intensidad por las ramas que tengan menos resistencia, y tal situacion llevara siempre a producir una menor resistencia equivalente.

5 0
3 years ago
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