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2 years ago

Find the equation of a line perpendicular to 2x – 3y = 21 that passes through the point (2,8).

Mathematics

1 answer:

kramer2 years ago

6 0

Answer:

y = -3/2x + 11

Step-by-step explanation:

2x - 3y = 21 => 3y = 2x - 21 => y = 2/3x - 7

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of perpendicular line is -3/2

y = mx + b

y = -3/2x + b

Using (2,8)

8 = -3/2(2) + b

8 = -3 + b

b = 11

y = -3/2x + 11

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Given:

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• BD = x + 3

Let's solve for x.

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$\frac{AD}{BD}=\frac{BD}{DC}$

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Plug in the values and solve for x:

$\begin{gathered} (x+3)^2=3*27 \\ \\ (x+3)^2=81 \end{gathered}$

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ANSWER:

d. 6

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Find the equation of a line perpendicular to 2x – 3y = 21 that passes through the point (2,8).​

Find the equation of a line perpendicular to 2x – 3y = 21 that passes through the point (2,8).