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Bezzdna [24]
3 years ago
7

Find the equation of a line perpendicular to 2x – 3y = 21 that passes through the point (2,8).​

Mathematics
1 answer:
kramer3 years ago
6 0

Answer:

y = -3/2x + 11

Step-by-step explanation:

2x - 3y = 21 => 3y = 2x - 21 => y = 2/3x - 7

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of perpendicular line is -3/2

y = mx + b

y = -3/2x + b

Using (2,8)

8 = -3/2(2) + b

8 = -3 + b

b = 11

y = -3/2x + 11

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Answer:

Area of the shades region = 244.6 ft²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle ABCD- Area of the right angle triangle DEC

Area of the rectangle = Length × width

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By applying Pythagoras theorem in the right triangle DEC,

(Hypotenuse)² = (leg 1)² + (leg 2)²

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(29.8)² = DE² + (28)²

888.04 = DE² + 784

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Area of ΔDEC = \frac{1}{2}(\text{Base})(\text{Height})

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Area of the shades region = 387.4 - 142.8

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What is 5906+689*56/2-3
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Hope this helps. - M
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