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luda_lava [24]
2 years ago
12

Why should you do you should

Physics
1 answer:
uranmaximum [27]2 years ago
8 0
One does not simply should you do you should
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Please help meeeee will mark as brainliest​
Katyanochek1 [597]

Answer:

a) pressure means force acted on a body per unit area

6 0
3 years ago
A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i
sammy [17]

Answer:

-0.25 rad/s^2

Explanation:

The equivalent of Newton's second law for rotational motions is:

\tau = I \alpha

where

\tau is the net torque applied to the object

I is the moment of inertia

\alpha is the angular acceleration

In this problem we have:

\tau = -12.5 Nm (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

I=50.0 kg m^2 is the moment of inertia

Solving for \alpha, we find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2

3 0
3 years ago
a 6.7kg object moves with a velocity of 8 m/s. whats its kinetic energy?(A)26.8J(B)214.4J(C)167.5J(D)53.6J
Ne4ueva [31]
The answer in (B)214.4J


I hope this helped have a nice day!
6 0
3 years ago
Read 2 more answers
Can anyone answer this for my friend course I am not sure of what I did I don’t take physics but I did it
kogti [31]

Answer:

the total travled is 2.75

Explanation:

because if you divide 110 by 40 you get 2.75

3 0
3 years ago
Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay
Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, m_1=0.205\ kg

Speed of the model, u_1=0.72\ m/s

Mass of another model, m_2=0.32\ kg

Initial speed of another model, u_2=0

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0
3 years ago
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