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elena55 [62]
3 years ago
6

Why can you see glass and your reflection

Physics
1 answer:
Schach [20]3 years ago
8 0
<span>Glass is transparent meaning light passes through it and therefore you can see through it, but some light reflects back and if the surface is very smooth as glass often is then the light reflected back can be seen as a reflected image.</span>
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ehidna [41]
An example of something that is not a proton would be an electron. It has a negative charge and has a charge of 1.6X10^-19 Coulombs.
6 0
3 years ago
You notice that the price of Blu-ray players falls and the quantity of Blu-ray players sold increases. This set of observations
satela [25.4K]

Answer:

Option C

Explanation:

When this type of situation occurs where the price falls and the sale of a product increases then a shift is observed in the supply curve towards right as a result of this shift there is a need to shift down the demand curve

Thus When supply curve is shifted to the right the demand curve is moved down accordingly.

6 0
3 years ago
A particle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. its initial position
Nesterboy [21]

The position of the object at time t =2.0 s is <u>6.4 m.</u>

Velocity vₓ of a body is the rate at which the position x of the object changes with time.

Therefore,

v_x= \frac{dx}{dt}

Write an equation for x.

dx=v_xdt\\ x=\int v_xdt

Substitute the equation for vₓ =2t² in the integral.

x=\int v_xdt\\ =\int2t^2dt\\ =\frac{2t^3}{3} +C

Here, the constant of integration is C and it is determined by applying initial conditions.

When t =0, x = 1. 1m

x= \frac{2t^3}{3} +C\\ x_0=1.1\\ x= (\frac{2t^3}{3} +1.1)m

Substitute 2.0s for t.

x= (\frac{2t^3}{3} +1.1)m\\ =\frac{2(2.0)^3}{3} +1.1\\ =6.43 m

The position of the particle at t =2.0 s is <u>6.4m</u>




5 0
3 years ago
How is voltmeter connected in the circuit to measure the potential difference between two points?
34kurt

Voltmeter is used to find the potential difference between two points.

We always connect it in parallel to the points where we need the potential difference.

Here in order to make the reading accurate we can increase the resistance of voltmeter so that it can not withdraw any current from the circuit.

7 0
3 years ago
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vichka [17]

As the ball is moving in air as well as we have to neglect the friction force on it

So we can say that ball is having only one force on it that is gravitational force

So the force on the ball must have to be represented by gravitational force and that must be vertically downwards

So the correct FBD will contain only one force and that force must be vertically downwards

So here correct answer must be

<em>Diagram A shows a box with a downward arrow. </em>

8 0
3 years ago
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