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alexdok [17]
3 years ago
6

Suppose a runner completes one lap around a 400-m track in a time of 50 s. Calculate the average speed of the runner.

Physics
1 answer:
suter [353]3 years ago
6 0

Answer:

8m/s

Explanation:

Average Speed = distance / time = 400/50 = 8m/s

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What causes the disease bronchitis?
Ilia_Sergeevich [38]

Answer:

Acute bronchitis can result from: a virus, for example, a cold or flu virus. a bacterial infection. exposure to substances that irritate the lungs, such as tobacco smoke, dust, fumes, vapors, and air pollution.

Explanation:

3 0
3 years ago
What is the terminal velocity of blood? A. 8.9 feet/seconds B. 9.8 feet/seconds C. 25.1 feet/second D. 52.1 feet/seconds
goblinko [34]

Answer:

the answer is c) 25.1 feet/second

Explanation:

because the blood droplets can not increase speed past terminal velocity 100.

3 0
3 years ago
What is the formula of Kinetic Energy​
Andre45 [30]

K.E = ½ mv²

Explanation:

The formula of Kinetic Energy

K.E = ½ mv²

Where,

m = mass of object

v = velocity of object

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<u>-TheUnknown</u><u>Scientist</u>

8 0
3 years ago
Read 2 more answers
In addition to gravity, what is the other predominant force that affects the motion of a pendulum?
konstantin123 [22]

When we're working problems that involve a pendulum, we almost always IGNORE anything else besides gravity.  

Anything else besides gravity that could influence the motion of a pendulum is something that we would eliminate if we could.

Those are air resistance, mass of the string, friction at the top suspension point, and the Coriolis force, due to the Earth's rotation, that tries to change the plane of the pendulum's swing.

This question is probably fishing for the answer "<em>friction</em>".

7 0
3 years ago
A CD-ROM drive in a computer spins the 12-cm-diameter disks at 9500 rpm. Find acceleration in units of g that a speck of dust on
NeTakaya
The net force on an object is:
F = ma
The only force acting on the speck of dust as it is lays on the CD is centripetal force given by:
F = (mv²)/r
Equating the two
ma = (mv²)/r
We get:
a = v²/r
v is the linear velocity in this case; however, we can calculate only the angular velocity with the given data. Therefore, we must use:
v = ωr; where
ω = 2πf; f is the rotations per second
f = 9500 / 60
f = 950/6
ω = 2π(950/6)
ω = (950π)/3
v = (950π)/3 × 0.12
v = 38π
a = (38π)²/0.12
a = 1.2 × 10⁵ m/s²
To express this in terms of gravitational acceleration, we divide by the value of gravitational acceleration, 9.81
a = 1.2 × 10⁴ g
4 0
3 years ago
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