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myrzilka [38]
3 years ago
7

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric

al air tank that measures 68.0cm wide. The biologist estimates she will need 4700.L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
bixtya [17]3 years ago
8 0

Answer:

the pressure to which this volume of air must be compressed in order to fit into the air tank is 28.5478 atm

Explanation:

the solution is attached in the Word file

Download docx
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Which is the empirical formula for a compound that contains 64.75g nitrogen and 185.25 oxygen
Svetach [21]

Answer:

What is the formula for a compound that contains 64.75 g nitrogen and 185.25 g oxygen? D. N2O5

The name of a hydrate is calcium chloride dihydrate. What is its formula? B. CaCl2 x 2H20

Explanation:

BRAINLIEST PLZZZZ

5 0
3 years ago
72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
Given any two elements within a group, is the element with the larger atomic number likely to have a larger or smaller atomic ra
zhenek [66]

Answer:

Atomic radius of sodium = 227 pm

Atomic radius of potassium = 280 pm

Explanation:

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

Consider the example of sodium and potassium.

Sodium is present above the potassium with in same group i.e, group one.

The atomic number of sodium is 11 and potassium 19.

So potassium will have larger atomic radius as compared to sodium.

Atomic radius of sodium = 227 pm

Atomic radius of potassium = 280 pm

3 0
3 years ago
the double bond in ethene is made up of a pi bond and a sigma bond formed by lateral overlap of two p orbitals
Deffense [45]

The unhybridized pz orbitals on each carbon overlap to a π bond (pi).The sigma bond framework of the ethylene molecule is produced by the overlap of hybrid orbitals or by the interaction of a hybrid orbital and a 1s hydrogen orbital.

Each carbon still has its unhybridized pz orbital, though. Sigma bond are typically the only types of single bonding between atoms. One sigma bond and two pi bonds make up triple bonds. One sigma () bond makes up a single bond, one and one pi () bond makes up a double bond, and one and two bonds make up a triple bond.

To learn more about bond, click here.

brainly.com/question/10777799

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3 0
2 years ago
Urea, CH4N2O (s), is manufactured from NH3 (g) and CO2 (g). H2O (l) is another product of this reaction. An experiment is starte
Katarina [22]

Answer:

a. 4.41 g of Urea

b. 1.5 g of Urea

Explanation:

To start the problem, we define the reaction:

2NH₃ (g) +  CO₂ (g) → CH₄N₂O (s)  +  H₂O(l)

We only have mass of ammonia, so we assume the carbon dioxide is in excess and ammonia is the limiting reactant:

2.6 g . 1mol / 17g = 0.153 moles of ammonia

Ratio is 2:1. 2 moles of ammonia can produce 1 mol of urea

0.153 moles ammonia may produce, the half of moles

0153 /2 = 0.076 moles of urea

To state the theoretical yield we convert moles to mass:

0.076 mol . 58 g/mol = 4.41 g

That's the 100 % yield reaction

If the percent yield, was 34%:

4.41 g . 0.34 = 1.50 g of urea were produced.

Formula is (Yield produced / Theoretical yield) . 100 → Percent yield

3 0
3 years ago
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