All categories

3 years ago

Which of the following does NOT reflect a possible relationship within a circle-

Mathematics

1 answer:

Anton [14]3 years ago

3 0

Answer:

Step-by-step explanation:

B does not represent a possible relationship within a circle. The circumference of B, based upon the given d = 7 in, is 21.99 in, not 19.5 in.

You might be interested in

How do you write eight hundred ninety-three thousand, five hundred thirty-seven in number form

Zepler [3.9K]

893,537 i believe is the correct form

6 0

3 years ago

Read 2 more answers

HELP PLEASE QUICKKKKKK

Gnesinka [82]

Answer:

lkfbnrld/kgnvr/slkbvluydcfgiufhvgukrghoudgb

8 0

3 years ago

Rick is building a scale model of the Alamo for his Texas History class. In this model, he is using a scale in which 3 inches re

motikmotik

Answer:

18 inches

Step-by-step explanation:

Rick is building a scale model of the Alamo.

We are given a scale that 3 in. = 15 ft.

The length of the Alamo is 90 feet.

What is the length of the scale model in inches?

So we know that for every 15 feet, 3 inches are actually used in the project and we need a total of 90 feet. To solve, we need to find how many times 15 goes into 90, in which the number it multiplies to will apply to the inches.

15 * ? = 90

90 / 15

It takes 15 6 times to get to 90, meaning that we need to multiply 3 inches 6 times to find the actual length of the scale model in inches.

3 * 6

18 inches.

8 0

3 years ago

An 8.5 centimeter green bean pod contains peas that average

Aleksandr-060686 [28]

Answer:

18 peas

Step-by-step explanation:

18.89 peas are in the pod, or about 18 peas, because you can divide 8.5 by 0.45 and get 18.8 recurring, or about 18.89, or 18

4 0

4 years ago

HELP. How long is the minor axis for the ellipse shown below?

kifflom [539]

Given:

The equation of ellipse is

$\dfrac{(x+4)^2}{25}+\dfrac{(y-1)^2}{16}=1$

To find:

The length of the minor axis.

Solution:

The standard form of an ellipse is

$\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1$ ...(i)

where, (h,k) is center, if a>b, then 2a is length of major axis and 2b is length of minor axis.

We have,

$\dfrac{(x+4)^2}{25}+\dfrac{(y-1)^2}{16}=1$ ...(ii)

On comparing (i) and (ii), we get

$b^2=16$

Taking square root on both sides.

$b=\pm 4$

Consider only positive value of b because length cannot be negative.

$b=4$

Now,

Length of minor axis = $2b$

= $2(4)$

= $8$

So, the length of minor axis is 8 units.

Therefore, the correct option is B.

8 0

3 years ago