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Yuki888 [10]
4 years ago
5

There is no sound in the vacuum of space. Why? Sound must travel through something that vibrates. There is no energy in space. T

here is no air to vibrate the human eardrum. Space is too full of light energy.
Physics
1 answer:
Blababa [14]4 years ago
3 0

Sound must travel through a medium/body. Space is a vacuum so there is no medium/body for sound to travel through, so there is no sound.

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What is the definition of "gravitational potential energy"?
AVprozaik [17]
According to Georgia State University, gravitational potential energy<span> is the energy an object possesses because of its position in a gravitational field. This is most commonly in reference to an object near the surface of the Earth, where the gravitational acceleration is assumed to be constant at about 9.8 m/s2.</span>
5 0
3 years ago
Read 2 more answers
He blocked his man using a force of 23 N moving him backward 2 meters ,how much work did he do?
Paul [167]

Answer:

work done = force x distance

Explanation:

F = 23 N

D = 2m

W = 23 * 2 = 46 J

6 0
4 years ago
The buoyant force on an object fully submerged in a liquid depends on (select all that apply)
Natasha_Volkova [10]
2. The object's volume.
 3. The density of the liquid.  
Remember what the buoyant force is. It's the lifting force caused by the displacement of a fluid. I'm using the word fluid because it can be either a liquid or gas. For instance a helium balloon floats due to the buoyant force exceeding the mass of the balloon. So let's look at the options and see what's correct. 
 1. Object's mass
 * This doesn't affect the buoyant force directly. It can have an effect if the object's mass is lower than the buoyant force being exerted. Think of a boat as an example. The boat is floating on the top of the water. If cargo is loaded into the boat, the boat sinks further into the water until the increased buoyant force matches the increased mass of the boat. But if the density of the object exceeds the density of the fluid, then increasing the mass of the object will not affect the buoyant force. So this is a bad choice. 
 2. The object's volume.
 * Yes, this directly affects the buoyant force. So this is a good choice. 
 3. The density of the liquid.
 * Yes, this directly affects the buoyant force. You can drop a piece of iron into water and it will sink. You could also drop that same piece of iron into mercury and it will float. The reason is that mercury has a much higher density than water. So this is a good choice. 
 4. Mass of the liquid
 * No. Do not mistake mass for density. As a mental exercise, imagine the buoyant force on a small piece of metal dropped into a swimming pool. Now imagine the buoyant force on that same piece of metal dropped into a lake. In both cases, the buoyant force is the same, yet the lake has a far greater mass of water than the swimming pool. So this is a bad choice.
8 0
3 years ago
Why do fields store potential energy? an object in the field has charge, fields don’t store potential energy, stationary objects
SpyIntel [72]

Answer:

Hey

Your answer would be:

stationary objects within the field will move when realesed.

The reason why is because fields store potential energy as you know. when something is stationary it has potential, but when it is released that potential energy turns into kinetic energy.

this made me think of a funny joke:

A man was about to jump off of the Empire State Building when a physicist from below yield, Wait don't! you have so much potential!

lol always cracks me up.

6 0
3 years ago
Five liters of air at 50 c is warmed to 100c what is the new volume if the pressure remain constant
KonstantinChe [14]
To solve the problem, we can use Charle's law, which states that for an ideal gas at constant pressure the ratio between absolute temperature T and volume V remains constant:
\frac{T}{V}=k
For a gas transformation, this law can be rewritten as
\frac{T_1}{V_1}= \frac{T_2}{V_2} (1)
where 1 and 2 label the initial and final conditions of the gas.

Before applying the law, we must convert the temperatures in Kelvin:
T_1 = 50^{\circ}C + 273 = 323 K
T_2 = 100^{\circ}C+273=373 K
The initial volume of the gas is V_1 = 5 L, so if we re-arrange (1) we find the new volume of the gas:
V_2 = V_1  \frac{T_2}{T_1}=(5 L) \frac{373 K}{323 K}=5.77 L
8 0
3 years ago
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