Answer:
Molar mass of bromine is equal to 
Explanation:
The molar mass of HBr is equal to the sum of atomic weight of Bromine.
Atomic Weight of hydrogen is equal to 
Atomic Weight of Bromine is equal to 
Molar mass of Bromine
= Atomic Weight of hydrogen + Atomic Weight of Bromine
Molar mass of Bromine 
Answer:
One mole of a substance is equal to 6.022 × 10²³ units of that substance (atoms, molecules, or ions)
Explanation:
This number is Avogadro's number. The concept of the mole can be used to convert between mass and number of particles. its used to compare very large numbers.
Answer:
11.58 L of N₂
Explanation:
We'll begin by calculating the number of mole in 37.2 g of magnesium. This can be obtained as follow:
Mass of Mg = 37.2 g
Molar mass of Mg = 24 g/mol
Mole of Mg =?
Mole = mass /Molar mass
Mole of Mg = 37.2 / 24
Mole of Mg = 1.55 moles
Next, we shall write the balanced equation for the reaction. This is illustrated below:
3Mg + N₂ —> Mg₃N₂
From the balanced equation above,
3 moles of Mg reacted with 1 mole of N₂.
Therefore, 1.55 moles of Mg will react with = (1.55 × 1)/3 = 0.517 mole of N₂
Thus, 0.517 mole of N₂ is need for the reaction.
Finally, we shall determine the volume of N₂ needed for the reaction as follow:
Recall:
1 mole of a gas occupies 22.4 L at STP.
1 mole of N₂ occupied 22.4 L at STP.
Therefore, 0.517 mole of N₂ will occupy = 0.517 × 22.4 = 11.58 L at STP
Thus, 11.58 L of N₂ is needed for the reaction.
Answer:
26 g
Explanation:
Write the balanced reaction first
CH4 + 2 O2 --> CO2 + 2 H2O
9.3g + 52.3g --> ? CO2
You must determine how much carbon dioxide can be made from each of the reactants. The maximum mass that can be made is the lower of the two.
From CH4:
9.3g CH4 (1molCH4/16.05gCH4) (1molCO2 / 1molCH4) (44.01g CH4 / 1molCO2) = 26 g
From O2:
52.3g O2 (1molO2/32gO2) (1molCO2/2molO2)(44.01g/1molCO2) = 36 g
Answer:
132 moles dhhdhsysushdgdgsgsgsgsgsv
