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OLEGan [10]
2 years ago
8

Which way of expressing concentration includes (a) volume of solution;

Chemistry
1 answer:
Sergio [31]2 years ago
6 0

Molarity and normality are the ways of expressing concentration which includes the volume of the solution.

As we know,

Molarity is defined as the number of moles of solute dissolved in 1L of the solution. Thus,

M = no. of moles of solution/ Volume of solution on litres.

while, Normality is the number of gram equivalents of the solute dissolved per litre of the solution.

N = Gram equivalent of the solute/ volume of solution in litres.

while, the other concentration expressing terms such as mole fraction, molality includes the mass of the solution and solvent respectively.

To know more about molarity visit the link:

brainly.com/question/9754178?referrer=searchResults

#SPJ4

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What are the empirical and molecular formulas of a hydrocarbon if combustion of 2.10 g of the compound yields 6.59 g co2 and 2.7
mariarad [96]

 The  empirical  formula    of hydrocarbon is  CH2

The  molecular formula  of the  hydrocarbon is  C6H12


    <u><em>Explanation</em></u>

Hydrocarbon  is  made up  of carbon and hydrogen


<h3><u><em> </em></u>Empirical formula  calculation</h3>

 Step 1:  find  the  moles   CO2  and  H2O

moles =mass/molar mass

moles   of CO2 =  6.59 g/ 44 g/mol = 0.15 moles

moles of H2O = 2.70 g / 18 g/mol =  0.15  moles

Step 2: Find the moles  ratio  of Co2:H2O  by diving  each mole by smallest mole(0.15)

that  is  for  CO2 = 0.15/0.15  =1

              For H2O = 0.15/0.15 =1

therefore  the mole ratio  of Co2 : H2O = 1:1  which  implies that 1 mole of Co2  and 1  mole of H2O is  formed  during combustion reaction.


From the  the law of mass conservation the number  of atoms in reactant side  must  be equal to  number of  atoms  in product side

therefore  since  there 1 atom  of C  in product side there  must be 1 atom of C  in reactant  side.

In addition  there is 2 H atom in product  side  which should be the  same  in reactant side.  

From information above the empirical formula is therefore = CH2


Molecular formula  calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n =  84 g/mol

n = 6

multiply the  each subscript  in CH2  by  6

 Therefore the molecular formula = C6H12




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A client has experienced excessive losses of bicarbonate and has subsequently developed an acid–base imbalance. How will this lo
IRISSAK [1]

The kidneys will excrete increased quantities of acid.

Explanation:

The kidneys will excrete excess H+ ions in the blood (remember H+ ions are responsible for acidity) until the acid-base balance is restored in the blood. Bicarbonates, on the other hand, will be aggressively  reabsorbed by the renal tubules as the excess H+ are being excreted.

The acid base balance is mainly determined by the quantities of H⁺ and HCO₃⁻ ions in teh blood. These ions come from the dissociation of carbonic acid formed when carbon dioxide from tissues is dissolved in blood plasma.

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The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?
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Answer:

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Explanation:

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Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

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where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

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How many oxygen atoms are present in a formula unit of calcium acetate?
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So we end up with a total of four oxygen atoms for this calcium acetate unit and guys that truly it for this one.

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