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UNO [17]
3 years ago
12

An empty beaker is placed on a top-pan balance. Some water is now poured into the beaker.What is the weight of the water? A. 0.0

44 kg B. 0.168 kg C. 0.0044N D. 0.44N
Physics
1 answer:
mario62 [17]3 years ago
6 0

Answer:

A. 0.044 kg

Explanation:

We need to subtract the sum of (beaker+water - empty beaker) which is 0.106 kg - 0.062 kg = 0.044 kg. The answer will not be written in Newton because this unit is used for force only and in this question w have to find the weight.

Hope it is enough.

Please mark me as brainliest.

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A bowler throws a ball down the lane toward the pins. The ball reaches the pins and slowly moves through them, knocking down the
Iteru [2.4K]

Answer:

First one

Explanation:

Maybe because example if a ball that has less mass bounces higher than the one w/more , then a bowling ball should be able with more force.

hope that helped:/

6 0
3 years ago
Individuals who smoke will have a higher frequency of developing cancer later in life.
ivanzaharov [21]
True


idk what you're asking
5 0
3 years ago
What is the state of matter that consists of a gas-like mixture of free electrons and nucle of atoms that have been stripped of
monitta
I think the answer is plasma which is a fourth state of matter.
5 0
3 years ago
A small 32-kilogram canoe broke free of its dock and is now floating downriver at a speed of 2.5 m/s. What is
marysya [2.9K]
<h3>Answer:</h3>

80 kgm/s

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of the Canoe is 32 kg
  • Speed of the Canoe is 2.5 m/s

We are required to calculate the momentum of the Canoe?

  • We need to know that momentum is the product of mass of an object and its speed.
  • Therefore;

Momentum = Mass × speed

Therefore;

Momentum = 32 kg × 2.5 m/s

                   = 80 Kgm/s

Thus, the momentum of the Canoe is 80 kgm/s.

6 0
3 years ago
At high speeds, a particular automobile is capable of an acceleration of about 0.540 m/s^2. At this rate, how long (in seconds)
Mama L [17]

Answer:

t = 6.68 seconds

Explanation:

The acceleration of the automobile, a=0.54\ m/s^2

Initial speed of the automobile, u = 91 km/hr = 25.27 m/s

Final speed of the automobile, v = 104 km/hr = 28.88 m/s

Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :

t=\dfrac{v-u}{a}

t=\dfrac{28.88-25.27}{0.54}

t = 6.68 seconds

So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.

5 0
3 years ago
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