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3 years ago

An object is dropped from a building and strikes the ground with a speed of 44 m/s. How tall is the building? *

Physics

1 answer:

nexus9112 [7]3 years ago

3 0

Answer:

d = 98.67m

Explanation:

equation:

vf^2 = vi^2 + 2ad

(44m/s)^2 = (0m/s)^2 + 2(9.81m/s^2)(d)

1936m^2/s^2 = 19.62m/s^2(d)

divide both sides by 19.62m/s^2

d = 98.67m approximately

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Given

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$\tan \theta =1.687$

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