Answer:
1) A = 0.25 m², 2) V = 0.5 m³, 3) m = 1500 kg, 4) W = 14700 N,
5) P = 58800 Pa
Explanation:
1) The area of the base is square
A = L²
A = 0.5²
A = 0.25 m²
2) The block is a parallelepiped
V = A h
V = 0.25 2
V = 0.5 m³
3) Density is defined
rho = m / V
m = rho V
m = 3000 0.5
m = 1500 kg
4) The weight of a body is
W = mg
W = 1500 9.8
W = 14700 N
5) The pressure is
P = F / A
in this case the force is equal to the weight of the body
P = 14700 / 0.25
P = 58800 Pa
The answer is Galileo Galilei. Hope this helps :)
At the initial state: v1 = vf = 0.001053 m
3
/kg, h1 = hf = 467.11 kJ/kg, and s1 = sf = 1.4336 kJ/kgK.
The mass of the water is: m = V/v1 = 0.005/0.001053 = 4.7483 kg.
To find the final state, we will use the First Law:
Q12 = m(h2 - h1) for closed system undergoing a constant pressure process.
h2 = 1Q2/m + h1 = 2200/4.7483 + 467.11 = 930.43 kJ/kg.
At P2 = P1 = 150 kPa, this is a saturated mixture.
hf = 467.11 kJ/kg, hfg = 2226.5 kJ/kg, sf = 1.4336 kJ/kgK, and sfg = 5.7897 kJ/kgK
s2 = sf + sfg (h2 – hf )/hfg = 1.4336 + 5.7897(930.43 – 467.11)/2226.5 = 2.6384 kJ/kgK.
The entropy change of water is:
Delta Ssys= m(s2 – s1) = 4.7483(2.6384 – 1.4336) = 5.72 kJ/K.
V = 0, a increasing
a = 0
v increasing, a increasing
v decreasing, a decreasing
As you go from Radio waves across to Gamma eats : Wavelength decreases and frequency and energy increase.