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denis-greek [22]
3 years ago
8

Consider the following reaction: SO2Cl2(g)⇌SO2(g)+Cl2(g) A reaction mixture is made containing an initial [SO2Cl2] of 2.2×10−2M

. At equilibrium, [Cl2]= 1.3×10−2M .
Chemistry
1 answer:
lukranit [14]3 years ago
5 0
I think you want to ask about Keq. At equilibrium, we can know [SO2Cl2] is 2.2*10-2 M -1.3*10-2M=9*10^-3 M. And [SO2]=[Cl2]. So the Keq=1.88*10^-2.
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How many carbon atoms are in 6.5 moles of carbon?
musickatia [10]
Just do 6.5 * (6.02 * 10^23)
Sorry I don’t have a calculator on me
Type that into the calculator to get your answer
6 0
3 years ago
What is the rate of a reaction if the value of kis 0.1, [A] is 1 M, and [B] is 2 M?
mel-nik [20]

Answer:

D.  0.4 (mol/L)/S

Explanation:

You simply have to plug in the given values into the rate law.

Rate = k[A][B]

Rate = (0.1)(1)²(2)²

Rate = (0.1)(1)²(4)²

Rate = 0.4

8 0
3 years ago
What is the molarity when 8.0 moles of solute are dissolved in 1.5 liters of solution?
KonstantinChe [14]
5.3m is the right answer.
4 0
3 years ago
Read 2 more answers
Scientists have speculated that element 126 might have a moderate stability allowing it to be synthesized and characterized. Pre
Dennis_Churaev [7]

Answer:

[Og] 5g2 6f3 8s2 8p1

Explanation:

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5 0
3 years ago
1) Sodium hydroxide is deliquescent. A sample of 3.0 g was dissolved in 100 mL; 10 mL was titrated with 34.9 mL HCl 0.2 M. What
ELEN [110]

From the calculation, the percentage of water in the sodium hydroxide sample is 7%.

<h3>What is neutralization?</h3>

The term neutralization has to do with the reaction between an acid and a base to yiled salt and water.

Now we have  to apply the titration formula;

CAVA/CBVB = NA/NB

CA = concentration of acid

CB = concentration of base

VA = volume of acid

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

The reaction equation is; HCl + NaOH ----->NaCl + H2O

CAVANB = CBVBNA

CB = CAVANB /VBNA

CB = 34.9 * 0.2 M * 1/10 * 1

CB = 0.698 M

Number of moles = Conncentration * volume

= 0.698 M * 100/1000 L = 0.0698 moles

Mass = Number of moles * molar mass

Mass =  0.0698 moles * 40 g/mol = 2.79 g

percent of NaOH = 2.79 g/ 3g * 100/1 = 93%

Percent of water = 100- 93 = 7%

Learn more about neutralization: brainly.com/question/15395418

5 0
2 years ago
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