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4 years ago

PLEASE HELP ME I BEG PLEASE!!!!

Chemistry

2 answers:

slega [8]4 years ago

6 0

Decomposition

Evaporation

Its solid form is less dense than its liquid form.

The acid both accepts and donates a hydrogen ion.

That causes the oxidation of another element

sbH3

Both reduction and oxidation are the same process

True

true

cricket20 [7]4 years ago

3 0

1.Decomposition i think
2.boiling
3.It is a solid at room temperature and pressure.
4.The base donates a hydrogen ion.
5.That causes the oxidation of another element
6.MnO2
7.When a substance is reduced, electrons are lost.
8.True I think
9.False
10.True

Hope these are correct

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Fuel

VikaD [51]

Answer:

Part 1

Where we have that the phase temperature at which fuel 1 changes to liquid due to its low temperature after the energy transfer is reached, fuel 1 changes to liquid

Where we have that the temperature of fuel 2 is still above its gas to liquid phase transition temperature, the fuel in fuel 2 will remain gaseous

Part 2

The kinetic energy of the individual molecules in fuel 1 is less than the intermolecular forces holding the molecules of fuel 1 in the liquid state such that fuel 1 molecules undergoes phase transformation from gas to liquid

The kinetic energy of the molecules in fuel 2 is higher than the fuel 2 liquid state intermolecular forces fuel 2 does not undergo phase transformation and remain a gas

Explanation:

Part 1

Why fuel 1 change phase but fuel 2 stayed the same can be explained by the combination of the following physical phenomena

1) Specific heat capacity of the fuels

2) Phase transition temperature of the fuels

The energy transferred out, ΔQ, can be expressed as follows;

ΔQ = m·c·ΔT

Where;

m = The mass of the fuel

c = The specific heat capacity of the fuel

ΔT = The temperature change of the fuel

Therefore, the energy transferred out, for a given mass of fuel, is directly proportional to the specific heat capacity, and the temperature change

For a given amount of transferred energy, when the specific heat capacity is high, the temperature change will be low and vice versa

Taking the specific heat capacity of fuel 1, c₁ as lower than the specific heat capacity of fuel 2, c₂₂, we have;

For a given energy transferred out, when c₁ < c₂ then we have, ΔT₁ > ΔT₂

The temperature change of fuel 1 is more than the temperature change of fuel 2 and if both fuels where initially at the same temperature and have the same mass, the final temperature of fuel $T_{1f}$ will be lower than the final temperature of fuel 2, $T_{2f}$

2) The phase transition temperature is the temperature at which a material changes phase from solid to liquid, or liquid to gas and vice versa, and it is dependent on the intermolecular holding the molecules of the substances together

Whereby the phase temperature at which fuel 1 changes to liquid due to its low temperature after the energy transfer is reached, while the temperature in fuel 2 is still above its gas to liquid phase transition temperature, the gaseous fuel in fuel 1 will be changed to liquid, while the fuel in fuel 2 will remain gaseous

Part 2

After the energy is transferred out, the kinetic energy of the individual molecules in fuel 1 becomes lower than the intermolecular forces holding the molecules of fuel 1 in the liquid state and the fuel 1 molecules transforms from gas to liquid

However, after the given amount of energy is transferred out, the kinetic energy of the molecules in fuel 2 are still higher than the intermolecular forces that exists between the molecules of fuel 2 when in the liquid state, and therefore, fuel 2 remains gaseous

3 0

3 years ago

Explain why for static electricity to occur between two surfaces that are rubbed against each other, one of the materials has to

lianna [129]

The rubbing creates a negative charge that is carried by electrons. The electrons can build up t produce static electricity.

8 0

3 years ago

Given the following equation, what would be the theoretical yield in grams of acetylsalicylic acid (C9H8O4) that can be produced

Mariana [72]

Answer:

The correct answer is 2.6 g C₉H₈O₄

Explanation:

-First we have to write and to balance the chemical equation:

C₇H₆O₃ + C₄H₆O₃ ⇄ C₉H₈O₄ + C₂H₄O₂

-Then, we calculate the molecular masses of reactants and products:

1 mol C₇H₆O₃= (12 g/mol C x 7) + (1 g/mol H x 6) + (16 g/mol O x 3)= 138 g

1 mol C₄H₆O₃= (12 g/mol C x 4) + (1 g/mol H x 6) + (16 g/mol O x 3)= 102 g

1 mol C₉H₈O₄= (12 g/mol C x 9) + (1 g/mol H x 8) + (16 g/mol O x 4)= 180 g

1 mol C₂H₄O₂= (12 g/mol C x 2) + (1 g/mol H x 4) + (16 g/mol O x 2)= 60 g

The mass balance is correct because:

mass reactants = mass products

138 g + 102 g = 180 g + 60 g

240 g = 240 g

-Now we use the masses from the chemical equation to calculate how reactant we need. We know that 138 g of salicylic acid (C₇H₆O₃) react with 102 g of acetic anhydride (C₄H₆O₃). So, the grams of acetic anhydride we need to react with 2 g of salicylic acid will be:

138 g C₇H₆O₃------------------- 102 g C₄H₆O₃

2.0 g C₇H₆O₃ -------------------- x= (2.0 x 102)/138 = 1.48 g C₄H₆O₃

If we compare, the amount of C₄H₆O₃ we need (1.48 g) is lesser than the amount we have (8 g), so C₄H₆O₃ is the excess reactant and C₇H₆O₃ is the limiting reactant.

- Finally, we use the limiting reactant to calculate the theoretical yield in grams of C₉H₈O₄. From the chemical equation, we know that 138 g C₇H₆O₃ yield 180 g of C₉H₈O₄. We have 2.0 g, so:

138 g C₇H₆O₃------------------- 180 g C₉H₈O₄

2.0 g C₇H₆O₃ -------------------- x= (2.0 x 180)/138 = 2.6 g C₉H₈O₄

8 0

3 years ago

Read 2 more answers

One of the product chemicals is aluminum chloride, which is an eye and skin irritant that can cause chemical burns. What will pr

vagabundo [1.1K]

Explanation:

Since, aluminium chloride is an eye and skin irritant. Therefore, it is better to follow safety measures while dealing with such a chemical.

Hence, it is good to wear a lab coat while working in a laboratory and wear chemical resistant gloves so that our skin does not come in contact with the chemical.

Also, safety glasses will prevent the eyes if there is spurting of chemical.

Thus, we can conclude that chemical-resistant gloves, a lab coat, and safety glasses will prevent you from coming into contact with the given hazard.

5 0

3 years ago

Read 2 more answers

The given potentials are observed for a calomel electrode: E ° = 0.268 V and E ( saturated KCl ) = 0.241 V . Use this informatio

Anvisha [2.4K]

Answer: The E for Silver-silver Chloride electrode = 0.287 V

Explanation:

Silver/Silver Chloride (Ag/AgCl) with a value for E° that is actually +0.222 V or approximately 0.23 V has the actual potential of the half-cell prepared in this way as +0.197 V vs SHE, (Standard Hydrogen Electrode) which arises because in addition to KCl, there is the contribuion of AgCl to the chloride activity, which isn't exactly unity.

Therefore, the E for the Ag/AgCl electrode would approximately equal 0.287 V

4 0

3 years ago