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Goshia [24]
2 years ago
13

HELP PLEASE

Physics
1 answer:
katovenus [111]2 years ago
6 0
1.80 If I had to guess
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A mass m is placed at the rim of a frictionless
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Answer:

Explanation:

at collision, m has a velocity of √2gR

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The stationary mass (3m) will depart at twice the system center of mass velocity

v(3m) = ½√2gR   ANSWER B

The relative velocity before the collision will be the negative of the relative velocity after the collision.

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An inclined plane makes an angle of 30.0º with the horizontal. 
Wittaler [7]

The force required to push the box upward is 145.3N and the force to pus the box downward is -109.3N

Data given;

  • mass = 15kg
  • angle = 30 degree
  • acceleration = 1.2 m/s^2
  • acceleration due to gravity = 9.8 m/s^2

<h3>Force against gravity</h3>

To move the plane upward, the box will move against gravity.

F = F - mgcos X\\&#10;ma = F - mg cosX

Let's solve for F

ma = F - mgcosX\\&#10;15*1.2 = F - 15*9.8 * cos 30\\&#10;18 = F - 127.30\\&#10;F = 18 + 127.30\\&#10;F = 145.3N

<h3>Force towards gravity</h3>

When the force pushes the box down the inclined plane, it moves towards gravity.

F = F + mgcosX\\&#10;ma = F + mgcosX\\&#10;15*1.2 = F + 15*9.8*cos30\\&#10;F = -109.3N

The force required to push the box upward is 145.3N and the force required to push the box downward is -109.3N

Learn more on force across an inclined plane here;

brainly.com/question/11888124

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What would happen if you changed the position of the screen, but kept the other factors the same?
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Answer:

I wish I could help but iam srry

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