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DIA [1.3K]
2 years ago
11

There are 900 seats on a train. 540 of the seats are empty. What percentage of the seats on the train are empty?

Mathematics
2 answers:
ANEK [815]2 years ago
4 0

60% of the seats on the train are empty

you have to divide 900 by 9 to get 100 because percents are out of 100, then you have to divide 540 by 9 also.

miss Akunina [59]2 years ago
4 0

Answer:

60%

Step-by-step explanation:

Because there are 540 empty, and 900 total, you need to divide 540 by 900.

540/900=54/90=6/10=60/100

When you get 60/100, or 0.6, you know that it is 60 percent because percent is out of 100.

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There are 50 seats on the tour bus. You reserve 2/5 of the seats How many seats did you reserve

6 0
3 years ago
What is the slope of the line passing through points A(−18,24) and B(16,−8)?
Anastaziya [24]
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M= --------- = ----------- = ------ = --------------- = ------
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6 0
3 years ago
A uniform distribution is defined over the interval from 6 to 10.
scoundrel [369]
Are you given an equation?
6 0
2 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
Amanda is a cabinetmaker. She makes cabinets using one of three types of wood: birch, maple, or cherry. She can finish each type
padilas [110]
Assume that each material in each category has an equal chance of being selected.

Categories:
(a) Type of wood used to make the cabinet: birch, maple, cherry.
     Each type of wood has a probability of 1/3 to be selected.
(b) Type of finish: transparent, semi-transparent.
    Each type of finish has a probability of 1/2 to be selected.
(c) Knob: bronze, steel, wood.
     Each material has 1/3 probability to be selected.

Each event (selecting material for the cabinet, for the finish, and for the knob) is an independent event.

Therefore
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6 0
3 years ago
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