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malfutka [58]
2 years ago
14

1) Which of the following statements about gases is false?

Chemistry
1 answer:
MrMuchimi2 years ago
8 0

Answer:

E

Explanation:

Not all gases are colourless and odourless at room temperature. Chlorine gas has a characteristic greenish-yellow colour at room temperature, hydrogen sulfide on the other hand has a characteristic pungent odour at room temperature

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A radioactive nuclide has 53 protons and 78 neutrons. Which is the symbol of this nuclide?
Aleksandr [31]

<em>Answer:</em>

Symbol =  I

<em>Explanation:</em>

<em>Isotopes</em> are those substances which have same atomic number (Numbers of protons) and different masses (Number of proton + numbers of neutrons).

  • Iodine also have many isotopes like

<em>Iodine-125</em> that contain 53 protons, 72 neutrons.

<em>Iodine-128</em>  that contain 53 protons, 75 neutrons.

<em>Iodine-129 </em> that contain 53 protons, 76 neutrons.

<em>Iodine-131</em> that contain 53 protons, 78 neutrons.

<em>Summary:</em>

  • Here the Iodine-131 is correct answer of this question.

5 0
4 years ago
Read 2 more answers
An ionic bond would form between which pairs of elements? atomic number 4 and atomic number 18 atomic number 7 and atomic number
weeeeeb [17]

Answer:

atomic number 8 and atomic number 12

Explanation:

atomic number 8 and atomic number 12 , element with the atomic number 8 is oxygen, and the element with atomic number 12 is Magnesium

Magnesium has low ionization energy, hence higher tendency to loose its two outermost electrons to form positive ion.

Oxygen has high electron affinity, hence higher tendency to accept or gain electrons to form negative ion.

The electronegativity difference between the element with atomic number 8 and element with atomic number 12 is greater for the formation of ionic bond

4 0
4 years ago
The label on a pressurized can of spray disinfectant warns against heating the can above 130 degree fahrenheit . What are the co
Leviafan [203]

Answer : The temperature in degree Celsius and Kelvin is, 54.44^oC\text{ and }327.59K respectively.

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

where,

^oF = temperature in Fahrenheit  

^oC = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273.15+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in Fahrenheit is, 130

Now we have to determine the temperature in degree Celsius.

^oC=(^oF-32)\times \frac{5}{9}

^oC=(130^oF-32)\times \frac{5}{9}

^oC=54.44

Now we have to determine the temperature in Kelvin.

K=273.15+^oC

K=273.15+(54.44^oC)

K=327.59

Therefore, the temperature in degree Celsius and Kelvin are, 54.44^oC\text{ and }327.59K

3 0
3 years ago
How is hydrogen in heavy water different from hydrogen in normal water?
tatyana61 [14]

Answer:

I'd say the correct answer is A

Explanation:

hope this helps:)

sorry if its wrong:(

6 0
3 years ago
Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces
Alchen [17]

The question is incomplete, here is the complete question:

Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 5.0 L flask with 2.2 atm of ammonia gas and 2.4 atm of oxygen gas at 44.0°C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of nitrogen gas to be 0.99 atm.

Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.

<u>Answer:</u> The pressure equilibrium constant for the reaction is 32908.46

<u>Explanation:</u>

We are given

Initial partial pressure of ammonia = 2.2 atm

Initial partial pressure of oxygen gas = 2.4 atm

Equilibrium partial pressure of nitrogen gas = 0.99 atm

The chemical equation for the reaction of ammonia and oxygen gas follows:

                    4NH_3(g)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(g)

<u>Initial:</u>               2.2          2.4

<u>At eqllm:</u>        2.2-4x      2.4-3x         2x        6x

Evaluating the value of 'x':  

\Rightarrow 2x=0.99\\\\x=0.495

So, equilibrium partial pressure of ammonia = (2.2 - 4x) = [2.2 - 4(0.495)] = 0.22 atm

Equilibrium partial pressure of oxygen gas = (2.4 - 3x) = [2.4 - 3(0.495)] = 0.915 atm

Equilibrium partial pressure of water vapor = 6x = (6 × 0.495) = 1.98 atm

The expression of K_p for above equation follows:

K_p=\frac{(p_{N_2})^2\times (p_{H_2O})^6}{(p_{NH_3})^4\times (p_{O_2})^3}  

Putting values in above equation, we get:

K_p=\frac{(0.99)^2\times (1.98)^6}{(0.22)^4\times (0.915)^3}\\\\K_p=32908.46

Hence, the pressure equilibrium constant for the reaction is 32908.46

5 0
3 years ago
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