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just olya [345]
3 years ago
5

Major product of free radical of chlorination of propene

Chemistry
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

For example, propene reacts with aqueous chlorine to form 1-chloro-2-propanol as the major product.

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What is the frequency of red light with a wavelength of 645 nm?
marin [14]

Answer:

4.64E14

Explanation:

First convert 645 nm to m = 6.4500E-7m. The equation for finding v with these values is the speed of light/wavelength. so 2.998E8/6.4500E-7m.

so your v or frequency would equal 4.64E14

Fun fact you know this is visible light because the visible light range is within the E14 range.

4 0
2 years ago
25,000cg is equal to _g
defon

Answer:

250 g

Explanation:

8 0
3 years ago
What does a positive H look like on a potential energy diagram?
Iteru [2.4K]

Answer:

D because i did this last week and got it right.

6 0
3 years ago
What’s the answer to this ( the proton has a ____ charge and it is found in the ____
Ksenya-84 [330]
ANSWER:

A proton has a "positive charge" and is found in the nucleus.

goodluck!!

support me by marking as brainliest!! :)
3 0
2 years ago
Identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent for the following equation
bazaltina [42]

The element that gains electrons, becomes reduced.

While the one which loses electrons, becomes oxidized.

In this equation,

CH₃OH + Cr₂O₇²⁻---- --> CH₂O + Cr³⁺.

By balancing the equation, we will get:

3CH₃OH + Cr₂O₇²⁻ + 8H⁺ --> 3CH₂O + 2Cr³⁺ + 7H₂O

Here the oxidation state of Cr changes from +6 to +3 that is it is being reduced thus serving as a oxidizing agent while other element retain their charges.

Here Cr₂O₇²⁻ is reduced while CH₃OH is oxidized.

So Cr₂O₇²⁻ serves as a oxidizing agent, while CH₃OH serves as reducing agent .

4 0
3 years ago
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