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3 years ago

Major product of free radical of chlorination of propene

Chemistry

1 answer:

tia_tia [17]3 years ago

6 0

Answer:

For example, propene reacts with aqueous chlorine to form 1-chloro-2-propanol as the major product.

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Calcular las fracciones molares de los componentes de una disolución formada por: 250 g de agua, 50 g de ácido acético y 25 g de

Minchanka [31]

The question is: Calculate the molar fractions of the components of a solution made up of: 250 g of water, 50 g of acetic acid and 25 g of sodium chloride.

Answer: The mole fraction of water, acetic acid and sodium chloride is 0.916, 0.054, and 0.028.

Explanation:

As number of moles is the mass of substance divided by its molar mass.

Therefore, moles of given species are calculated as follows.

The number of moles of water (molar mass = 18 g/mol):

$Moles = \frac{mass}{molar mass}\\= \frac{250 g}{18 g/mol}\\= 13.88 mol$

The number of moles of acetic acid (molar mass = 60.052 g/mol):

$Moles = \frac{mass}{molar mass}\\= \frac{50 g}{60.052 g/mol}\\= 0.832 mol$

The number of moles of sodium chloride (molar mass = 58.44 g/mol):

$Moles = \frac{mass}{molar mass}\\= \frac{25 g}{58.44 g/mol}\\= 0.427 mol$

Therefore, mole fraction of each component is calculated as follows.

Mole fraction of water:

$Mole fraction = \frac{moles of water}{Total moles}\\= \frac{13.88}{13.88 + 0.832 + 0.427}\\= \frac{13.88}{15.139}\\= 0.916$

Mole fraction of acetic acid:

$Mole fraction = \frac{moles of water}{Total moles}\\= \frac{0.832}{13.88 + 0.832 + 0.427}\\= \frac{0.832}{15.139}\\= 0.054$

Mole fraction of NaCl:

$Mole fraction = \frac{moles of water}{Total moles}\\= \frac{0.427}{13.88 + 0.832 + 0.427}\\= \frac{0.427}{15.139}\\= 0.028$

Thus, we can conclude that mole fraction of water, acetic acid and sodium chloride is 0.916, 0.054, and 0.028.

8 0

3 years ago

Alexus [3.1K]

I found this information:

Anaerobic respiration begins the same way as fermentation. The first step is still glycolysis, and it still creates 2 ATP from one carbohydrate molecule. However, instead of ending with glycolysis, as fermentation does, anaerobic respiration creates pyruvate and then continues on the same path as aerobic respiration.

After making a molecule called acetyl coenzyme A, it continues to the citric acid cycle. More electron carriers are made and then everything ends up at the electron transport chain. The electron carriers deposit the electrons at the beginning of the chain and then, through a process called chemiosmosis, produce many ATP. For the electron transport chain to continue working, there must be a final electron acceptor. If that acceptor is oxygen, the process is considered aerobic respiration.

Scientists believe that fermentation and anaerobic respiration are older processes than aerobic respiration.

I hope this help. :)

have a good day!

3 0

3 years ago

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PLEASE HELP ILL GIVE BRAINLIEST

hodyreva [135]

Answer:

Explanation:

5 0

2 years ago

7. De acuerdo con esta clasificación, no es un hidrocarburo A. CH3-CO-CH3 B. CH4 C. C6H6 D. CH3-CH2-CH3 8. No se considera como

devlian [24]

Answer:

Explanation:

4 0

3 years ago

Why Bohr's theory was inadequate?

Natalka [10]

Bohr’s theory was inadequate because it did not explain the energies absorbed and released by atoms with more than one electron. It worked well for hydrogen atoms but did not work when applied to more complex atoms.

6 0

3 years ago