Answer:
756.88 Volts will be the potential difference across each capacitor.
Explanation:

Q = Charge on capacitor
C = Capacitance
V = Voltage across capacitor
Capacitance of first capacitor = 
Charge of first capacitor = 
Voltage across first capacitor = 


Capacitance of first capacitor = 
Charge of second capacitor = 
Voltage across first capacitor = 


Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.
Total charge = Q

Total capacitance in parallel combination:

Potential across both capacitors = V

756.88 Volts will be the potential difference across each capacitor.
The answer is ”D”, “a higher frequency and a shorter wavelength.
The correct answer is D. 2200 Hz
Explanation:
The frequency of a wave is measured in hertz (Hz) and refers to how often a wave passes through a point during a specific time. This factor can be calculated if you divide the velocity of the wave by the wavelength (distance between crests) this means f (frequency) = v (velocity) / λ (wavelength).
f (frequency) = 242 m/s (velocity) / 0.11 (wavelegth)
f = 2200 Hz
According to this, the frequency of the wave, in this case, is 2200 Hz
Answer:
"A pendulum swinging back and forth" is an example of harmonic motion
X = Xo cos ω t
Explains the back and forth motion of the pendulum