Answer:3,600 Newtons
Explanation:
The net force acting on the car is
3×10^3squared
Newtons.
Force is defined as the product of the mass of the body and its aaceleration,⇒F=ma
Substituting the above given values we get,F=(1500kg) (2.0m /s^2 squared)=3000 N=3×10^3 squared N.
N=newtons
Answer:
Explanation:
q = 2e = 3.2 x 10^-19 C
mass, m = 6.68 x 10^-27 kg
Kinetic energy, K = 22 MeV
Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A
(a) time, t = 2.8 s
Let N be the alpha particles strike the surface.
N x 2e = q
N x 3.2 x 10^-19 = i t
N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8
N = 2.36 x 10^12
(b) Length, L = 16 cm = 0.16 m
Let N be the alpha particles
K = 0.5 x mv²
22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²
v² = 1.054 x 10^15
v = 3.25 x 10^7 m/s
So, N x 2e = i x t
N x 2e = i x L / v
N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)
N = 4153.85
(c) Us ethe conservation of energy
Kinetic energy = Potential energy
K = q x V
22 x 1.6 x 10^-13 = 2 x 1.5 x 10^-19 x V
V = 1.17 x 10^7 V
Answer:
6.136 mm
Explanation:
given,
frequency emitted by the bat = 5.59 x 10⁴ Hz
speed of sound = 343 m/s
smallest insect bat can hear will be equal to the wavelength of the sound the bat make.
λ = 6.136 mm
so, the smallest size of insect that bat can hear is equal to 6.136 mm
Answer: having to push a rough and heavy box across the floor to move it
Explanation:
The Friction force is any force that is in opposite direction of the motion of an object or fluid due to the contact of this object or fluid with other bodies.
In this sense, there are different types of friction force thath are useful in different situations:
-The <u>Static friction force</u> prevents surfaces from slipping across each other. For example, the friction between your feet and the floor keeping you from slipping.
-The <u>kinetic friction force</u> as the force that helps the tires in a moving vehicle to slow down and stop when necessary.
However, if you want to push a heavy box across the floor to move it, the friction force will not be useful at all.
Answer:
P = 140000 [Pa]
Explanation:
To solve this problem we must remember that pressure is defined as the relationship between Force on the area of a body.
In this particular problem, we are given the force acting on the upper surface of the block, including the force exerted by the atmospheric pressure.
P = F/A
where:
P = pressure [Pa] (units of Pascals)
F = force = 3.5*10⁴ [N]
A = area = 0.25 [m²]
P = 3.5*10⁴/0.25
P = 140000 [Pa]
