No, the combination lock is not appropriate. This is so as the repetition is allowed, neither permutation nor the combination rule holds true or valid.
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Answer:
Jenna needs 2 yards of ribbon to wrap 4 boxes.
Step-by-step explanation:
First, we can find how many inches of ribbon she needs.
18*4=72
She needs 72 inches of ribbon for 4 yards.
There are 36 inches in a yard.
72/36=2
Jenna needs 2 yards of ribbon to wrap 4 boxes.
M = -4/3 (slope stays the same)
so y= -4/3x + b
b = y intercept
without a point on the line I can’t figure out what exact line you were looking for but that equation with any value as b will give you a line parallel to the original.
Answer:
Since both equations are equal to y, we can set them equal to each other.
y =-3x +8
y = -5x -2
-3x +8 = -5x -2
Solve for x.To do this, we need to get x by itself. First, move all the numbers to one side of the equation, and all the variables to the other.
-3x +8 = -5x -2
Add 5x to both sides
-3x+5x +8=-5x+5x -2
2x+8=-2
Subtract 8 from both sides
2x+8-8 = -2-8
2x=-10
Now, all the numbers are on one side, with the variables on the other. x is not by itself, it is being multiplied by 2. To undo this, divide both sides by 2
2x/2= -10/2
x= -5
Now, to find y, substitute -5 in for x in one of the equations.
y = -5x -2
y= -5(-5) -2
y=25-2
y=23
Put the solution into (x,y)
<u><em>The solution is (-5, 23)</em></u>
Answer:
1. The volume of the pile is 4,399.7719 m^3
2. The number of sanders to be filled from a pile is 638
Step-by-step explanation:
Here, we firstly would calculate the volume of the pile
Mathematically, that will be;
V = 1/3 * pi * r^2 * h
from the question, h = 14.2
Mathematically, r = d/2
r = 34.4/2 = 17.2 m
So the volume will be:
V = 1/3 * 3.142 * 17.2^2 * 14.2
V = 4,399.7719 m^3
To find the number of sanders to be filled,
we simply divide the volume obtained by the volume a sander can take
That will be;
4,399.7719/6.9
= 637.6 which is 638
