Answer:
(a)
(b) 5220 j
(c) 1740 watt
(d) 3446.66 watt
Explanation:
We have given mass m = 290 kg
Initial velocity u = 0 m/sec
Final velocity v = 6 m/sec
Time t = 3 sec
From first equation of motion
v = u+at
So
(a) We know that force is given by
F = ma
So force will be
(b) From second equation of motion we know that
We know that work done is given by
W = F s = 580×9 =5220 j
(c) Time is given as t = 3 sec
We know that power is given as
(d) Time t = 1.5 sec
So
S= 1/2 x 182 x t = 1688.3
t = 1688.3 / 91
time = 18.55 seconds
Answer:
748.8 kJ
Explanation:
Kinetic energy is given by
where m is the mass of the body, v is the velocity
Substituting 2600 Kg for m and 24 m/s for velocity
Therefore, kinetic energy is 748.8 kJ
Huh? pls elaborate i don’t understand
Answer:
The net force acting on this object is 180.89 N.
Explanation:
Given that,
Mass = 3.00 kg
Coordinate of position of
Coordinate of position of
Time = 2.00 s
We need to calculate the acceleration
For x coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in x axis at 2 sec
For y coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in y axis at 2 sec
The acceleration is
We need to calculate the net force
The magnitude of the force
Hence, The net force acting on this object is 180.89 N.