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shtirl [24]
3 years ago
11

An electron is accelerated through a potential difference of 3.1 kV and directed into a region between two parallel plates separ

ated by 17 mm with a potential difference of 100 V between them. The electron is moving perpendicular to the electric field when it enters the region between the plates. What magnetic field is necessary perpendicular to both the electron path and the electric field so that the electron travels in a straight line?
Physics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer: 178.25*10^-6 T

Explanation: In order to solve this problem we have to take into account the equilibrium between the electric and magnetic forces in the electron, so it is given by:

Fm=evB

Fe=eE so

evB=eE the we have

v=E/B

Firsly we calculate the velocity of the electron before to get the parallel plates at 100V

eΔV=1/2*m*v^2 then

v=(2*eΔV/m)^1/2

v=(2*1.6*10^-19*3.1*10^3/9.1*10^-31)^1/2=33 *10^6 m/s

Then we can calculate B

B=E/v   E.d=V  where d is the separation between the plates and V is equal a 100V

B=V/(d*v)=100/(17*10^-3*33 *10^6)=178.25*10^-6 T

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Explanation:

Speed and velocity are two different quantities. In fact:

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Svetach [21]

Answer:

9.56\cdot 10^{-7} C

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Since the distance between the plates (1 cm) is very small compared to the side of the plates (19 cm), we can consider these two plates as two infinite sheets of charge.

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