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Diano4ka-milaya [45]
2 years ago
8

What type of salt would you get in a reaction between an oxide and hydrochloric acid?

Chemistry
1 answer:
grandymaker [24]2 years ago
3 0

Answer:

C. chloride i hopeit's right..

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Consider the positions of barium (Ba), sulfur (S), silicon (Si), and calcium (Ca) on the periodic table. The atoms of which elem
Rudiy27
Element      atomic number       position

Ba              56                             group 2, period 6

Ca              12                             group 2, period 3

S                16                             group 16, period 3

Si               `14                            group 14, period 3


Now, you need to know the properties of the different type of elements and the tendencies on the periodic table.


The metallic elements are, those placed on the left side of the periodic table, are the ones that release an electron more easily, so they will requiere less energy to give it up when forming chemical bonds.


The higher the metallic character the less the energy need to give up an electron.


The metallic character grows as the group number decreases (goes to the left) period increases (goes downward), so among the  elements considered, Barium will require the least amount of energy to give un an electron when forming chemical bonds.
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This tea kettle shows a change in the state of matter of water. Which part of the water cycle represents the same change in stat
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Which statement describes a property that is unique to metalloids?
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Metalloids are semiconductive.

Explanation:

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2.38g of black copper(iii) oxide is completely reduced to by hydrogen to give copper and water. What are the number of atoms of
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Calculate the de Broglie wavelength of a body of mass 1 kg moving with a velocity of
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Answer:

4.42 × 10⁻³⁷ m

Explanation:

Step 1: Given and required data

  • Mass of the body (m): 1 kg
  • Velocity of the body (v): 1500 m/s
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Step 2: Calculate the de Broglie wavelenght (λ) of the body

We will use de Broglie's equation.

λ = h / m × v

λ = (6.63 × 10⁻³⁴ J.s) / 1 kg × (1500 m/s) = 4.42 × 10⁻³⁷ m

6 0
2 years ago
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