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Diano4ka-milaya [45]
2 years ago
8

What type of salt would you get in a reaction between an oxide and hydrochloric acid?

Chemistry
1 answer:
grandymaker [24]2 years ago
3 0

Answer:

C. chloride i hopeit's right..

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What is the molarity when water is added to 4 moles of sodium chloride to make 0.5 liter of solution?
loris [4]
       If    0.5 L of solution contains 4 mol
then let     1 L of solution contain  x  mol
      
       ⇒    (0.5 L) x  = (4 mol) (1 L)

                         x  = (4 mol · L)  ÷  (0.5 L)

                         x  = 8 mol

Thus the molarity of the Sodium Chloride solution is 8 mol / L   OR  8 mol/dm³. 
7 0
3 years ago
Calcule la densidad del hidrógeno H2 en g/L a 327 mm Hg y 48ºc
tankabanditka [31]
<h3>The density of H₂ = 0.033 g/L</h3><h3>Further explanation</h3>

In general, the gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)

T = temperature, Kelvin  

n = N / No  

n = mole  

No = Avogadro number (6.02.10²³)  

n = m / MW

m = mass  

MW = molecular weight

For density , can be formulated :

\tt \rho=\dfrac{P\times MW}{R\times T}

P = 327 mmHg = 0,430263 atm

R = 0.082 L.atm / mol K

T = 48 ºC = 321.15 K

MW of H₂ =  2.015 g/mol

The density :

\rho=\dfrac{0,430263\times 2.015 }{0.082\times 321.15}\\\\\rho=0.033~g/L

4 0
3 years ago
When 200g water goes from a temperature 10C to 40C, is heat absorbed or released?
gayaneshka [121]

how would it be possible to even be absorbed?? the answer is released.

8 0
3 years ago
Which statement describes the relationship between microscopic and macroscopic phenomena?
sesenic [268]

Answer:

It's d

Explanation:

They have two different meaning and jobs

8 0
2 years ago
Arunner sprints 550 feet in 100 seconds. If the runner can hold this pace for an hour
Alex
<h3>Answer:</h3>

Distance traveled is 9.055 km

<h3>Explanation:</h3>

Speed is given by dividing distance by time.

The distance given is 550 ft and the time is 100 seconds.

Therefore; Speed = 550 ft ÷ 100 sec

                              = 5.5 ft/sec

We can calculate the distance the runner covered in one and half hour.

Time = 1.5 hours

But 1 hour = 3600 sec

1.5 hours = (1.5 × 3600)

               = 5400 sec

Distance is given by multiplying speed and time

Thus; Distance = 5.5 ft/sec × 5400 sec

                         = 29700 ft

But; 1 m = 3.28 ft

1000 m = 1 km

Therefore; 29700 ft will be equivalent to

 = 29700 ft/3.28 ft

= 9054.878 M

but 1000 m = 1 km

Thus, distance = 9054.878 ÷ 1000 m

                        = 9.055 km

6 0
3 years ago
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