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marusya05 [52]
2 years ago
8

Ivan pushes a dresser with full drawers across his carpeted floor. What could Ivan do to reduce the amount of friction between t

he dresser and the floor? Select two options. Place some smooth tiles under the dresser remove or turn off sources of wind move the dresser at a slower speed remove the drawers from the dresser.
Physics
2 answers:
aniked [119]2 years ago
7 0

Answer:

Place some smooth tiles under the dresser

Smooth surfaces, like smooth tile, are easy to slide over. They create very little friction. Rough surfaces like carpet create much more friction.

remove the drawers from the dresser

Weight affects friction in that friction is directly proportional to the weight of the load one is moving. So reduce the weight, reduce the friction.

Explanation:

Speed does not impact friction, so moving the dresser slower won't help. Wind has nothing to do with the scenario, so that's not a correct option.

Sveta_85 [38]2 years ago
5 0

Answer:

a d

Explanation:

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When decreasing electromagnetic radiation there is a(n)_______relationship between wavelength and frequency and the greater the
IceJOKER [234]

Answer:

Inverse proportion, greater

Explanation:

The relation between wavelength (λ) and frequency (ν) is given by

\nu = \frac{c}{\lambda }

Where c speed of light in vacuum.

We can see from this equation that wavelength and frequency are related inversely.

Now,

E= h \nu

Where 'E' is energy of electromagnetic radiation and 'h' is Planck's constant.

We can see from this equation that greater frequency (ν) will give greater electromagnetic radiation (E). As they are directly proportional.

Hence,

When decreasing electromagnetic radiation there is a(n) Inverse proportion relationship between wavelength and frequency and the greater the frequency, the greater energy the electromagnetic radiation has

5 0
3 years ago
Convert 3.5 km/hr to m/s
Nastasia [14]

Answer:

0.972222........

Explanation:

1. Convert km/h to m/h by multiplying by 1000

2. Divide by 60 so that you have 58.3333... meters per minute

3. Divide by 60 again so now you have 0.972222... m/s

8 0
3 years ago
Read 2 more answers
A box rests on the floor. If you pull sideways on the box with a 300 N force, but don't move it, what is the magnitude of the fr
Dahasolnce [82]

The magnitude of the frictional force is B) 300 N

Explanation:

For this problem, we just have to consider the forces acting on the box in the horizontal direction.

There are only two forces in this direction:

- The pull applied by the man, of magnitude F=300 N, forward

- The frictional force, F_f, acting backward

So the equation of motion for the box is

F-F_f = ma

where

m is the mass of the box

a is its acceleration

However, the box is at rest, so its acceleration is zero:

a = 0

This means therefore that

F-F_f=0

And so the magnitude of the frictional force is equal to the pulling force:

F_f = F = 300 N

Learn more about friction:

brainly.com/question/6217246

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#LearnwithBrainly

5 0
3 years ago
Three fire hoses are connected to a fire hydrant. Each hose has a radius of 0.014 m. Water enters the hydrant through an undergr
Makovka662 [10]

Answer:

Explanation:

The total fluid mass can be obtained by multiplying the mass flow rate by the time flow rate.

Mass flow rate is given as

m = ρAv

Where

m is mass flow rate

ρ is density

A is area and it is given as πr²

v is velocity

Then,

M = mt

Where M is mass and t is time

Them,

M = ρAv × t

M = ρ× πr² × v × t

Given that, .

Radius of pipe is

r = 0.089m

velocity of pipe is

v = 3.3m/s

Time taken is

t = 1 hour = 3600 seconds

Density of water is

ρ = 1000kg/m³

M = ρ× πr² × v × t

M = 1000 × π × 0.089² × 3.3 × 3600

M = 295,628.52 kg

M = 2.96 × 10^5 kg

8 0
4 years ago
A rocket sled accelerates at a rate of 49.0 m/s2 . Its passenger has a mass of 75.0 kg. (a) Calculate the horizontal component o
Katen [24]

Explanation:

It is given that,

Mass of the passenger, m = 75 kg

Acceleration of the rocket, a=49\ m/s^2

(a) The horizontal component of the force the seat exerts against his body is given by using Newton's second law of motion as :

F = m a

F=75\ kg\times 49\ m/s^2

F = 3675 N

Ratio, R=\dfrac{F}{W}

R=\dfrac{3675}{75\times 9.8}=5

So, the ratio between the horizontal force and the weight is 5 : 1.

(b) The magnitude of total force the seat exerts against his body is F' i.e.

F'=\sqrt{F^2+W^2}

F'=\sqrt{(3675)^2+(75\times 9.8)^2}

F' = 3747.7 N

The direction of force is calculated as :

\theta=tan^{-1}(\dfrac{W}{F})

\theta=tan^{-1}(\dfrac{1}{5})

\theta=11.3^{\circ}

Hence, this is the required solution.

8 0
4 years ago
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