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2 years ago

10

A cell contains the same DNA as its parent cell. This is a result of which process? mitosis meiosis gamete formation fertilizati

on

2 answers:

Sauron [17]2 years ago

4 0

Answer:

Mitosis

Explanation:

lesya692 [45]2 years ago

3 0

Answer:

Mitosis

Explanation:

A cell that contains the same DNA as its parent cell is a product of mitosis.

Mitosis is a cell division process that takes place in somatic cells.
In meiosis a single cell divides to produce two daughter cells each having the same DNA as the parent
Mitosis ensures that the same DNA is found between the parent
Mitosis is used for repairing and production of new cells.

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Choose all of the following mole ratios that are correct for the reaction given below. Be sure to choose all that apply.

Dennis_Churaev [7]

Answer:

2 moles NH3 = 1 mole of N2

3 moles of H2 = 1 mole of N2

3 moles of H2 = 2 moles of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Thus, we can say that:

1 mole of N2 = 3 moles of H2

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3 moles of H2 = 2 moles of NH3

Thus, considering the options given above, the right answers to the question are:

2 moles NH3 = 1 mole of N2

3 moles of H2 = 1 mole of N2

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3 years ago

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3 years ago

A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How

IrinaK [193]

Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $783J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

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$\Delta T$ = change in temperature = $T_2-T_1=(23.73-26.01)=-2.28^oC$

Now put all the given values in the above formula, we get:

$q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]$

$q=-4208.28J=-4.81kJ$

Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

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