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2 years ago

The picture above shows a water wave hitting the beach. Which of the following is true about this process?

Chemistry

1 answer:

dsp732 years ago

5 0

Answer:

C Beause energy can't be carred with the water to the shore

Explanation:

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A compound with the empirical formula ch2 has a molar mass of 98 g/mol what is the molecular formula for this compound ?

madam [21]

Approximate molecular masses:
Molecular mass of C = 12
Molecular mass of H = 1

Let n = moles required for CH₂.
Then
nCH₂ = 98
n(12 + 2*1) = 98
14n = 98
n = 7

Answer: The molecular formula is 7CH₂

7 0

3 years ago

Calculate the relative formula mass (Mr) of gold chloride (AuCl3).

Bas_tet [7]

Answer:

197 + (35.5×3) = 303.5

Explanation:

relative formula mass is the sum of the relative atomic masses of the atoms in the formula ( AuCl3 )

3 0

3 years ago

GIVING BRAINLIEST!! PLEASE HELP

LenaWriter [7]

Answer:

huh

Explanation:

8 0

3 years ago

Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?

mylen [45]

Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

Keq is the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

$Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}$

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

$Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}$

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

$Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

Therefore, Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

4 0

3 years ago

A chemist forms 16.6 g of potassium iodide by combining 3.9 g of potassium with 12.7 g of iodine. Show that these results are co

bezimeni [28]

3.9 g + 12.7 g = 16.6 g

The sum of the masses of potassium and iodine equals the mass of the product, potassium iodide. The results are consistent with he law of conservation of mass.

Hope this heeeelllllllpppppppp

3 0

3 years ago